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An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB is
- a)1200 m
- b)0.33 km
- c)3.33 km
- d)33 km
Correct answer is option 'C'. Can you explain this answer?
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An aeroplane is flying horizontally with a velocity of 600 km/h and at...
First resolve the motion is 2 components 1st horizontal and 2nd vertical .
1st vertical component :-
As there is no velocity in the vertical direction so in Italy velocity there will be zero but the gravitational force is acting in that direction so the accleration in the vertical direction will be g(10)m/s^2
Apply equation of motion here and u will get the time i.e about 19.79sec .
Then we have no acceleration in the horizontal direction so simply
Velocity[horizontal] =distance /time
Hence distance will be 3.3km approx
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An aeroplane is flying horizontally with a velocity of 600 km/h and at...
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An aeroplane is flying horizontally with a velocity of 600 km/h and at...
To solve this problem, we can break it down into two components: horizontal motion and vertical motion.
1. Horizontal Motion:
The velocity of the airplane in the horizontal direction is given as 600 km/h. This means that the airplane covers a distance of 600 km in one hour. We need to determine the time it takes for the bomb to strike the ground, so we can use the horizontal motion equation:
Distance = Velocity x Time
Since the distance covered in the horizontal direction is equal to the distance AB, we can rewrite the equation as:
AB = 600 km/h x Time
2. Vertical Motion:
The bomb is released from a height of 1960 m. We need to find the time it takes for the bomb to reach the ground. We can use the vertical motion equation:
Height = (Initial Velocity x Time) + (0.5 x Acceleration x Time^2)
In this case, the initial velocity is zero because the bomb is released from rest. The acceleration is due to gravity and is approximately 9.8 m/s^2. We can rearrange the equation to solve for time:
1960 m = 0.5 x 9.8 m/s^2 x Time^2
Simplifying the equation, we get:
Time^2 = (2 x 1960 m) / 9.8 m/s^2
Time^2 = 400
Time = 20 s
3. Calculating AB:
Now that we have the time it takes for the bomb to reach the ground, we can substitute it into the horizontal motion equation to find AB:
AB = 600 km/h x 20 s
AB = (600 km/h x 1000 m/km) x (20 s / 3600 s/h)
AB = 3333.33 m
Therefore, the distance AB is approximately 3.33 km. Hence, the correct answer is option 'C'.
1. Horizontal Motion:
The velocity of the airplane in the horizontal direction is given as 600 km/h. This means that the airplane covers a distance of 600 km in one hour. We need to determine the time it takes for the bomb to strike the ground, so we can use the horizontal motion equation:
Distance = Velocity x Time
Since the distance covered in the horizontal direction is equal to the distance AB, we can rewrite the equation as:
AB = 600 km/h x Time
2. Vertical Motion:
The bomb is released from a height of 1960 m. We need to find the time it takes for the bomb to reach the ground. We can use the vertical motion equation:
Height = (Initial Velocity x Time) + (0.5 x Acceleration x Time^2)
In this case, the initial velocity is zero because the bomb is released from rest. The acceleration is due to gravity and is approximately 9.8 m/s^2. We can rearrange the equation to solve for time:
1960 m = 0.5 x 9.8 m/s^2 x Time^2
Simplifying the equation, we get:
Time^2 = (2 x 1960 m) / 9.8 m/s^2
Time^2 = 400
Time = 20 s
3. Calculating AB:
Now that we have the time it takes for the bomb to reach the ground, we can substitute it into the horizontal motion equation to find AB:
AB = 600 km/h x 20 s
AB = (600 km/h x 1000 m/km) x (20 s / 3600 s/h)
AB = 3333.33 m
Therefore, the distance AB is approximately 3.33 km. Hence, the correct answer is option 'C'.
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An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground, a bomb is released from it. The bomb strikes the ground at point B. The distance AB isa)1200 mb)0.33 kmc)3.33 kmd)33 kmCorrect answer is option 'C'. Can you explain this answer?
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