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The vapour pressure of a solvent decreased by 10mmHg when a nonvolatile solute was added to the solvent. The mole fraction of the solute in the solution
is 0.2. What would be the mole fraction of the solvent if the decrease in the vapour pressure is to be 20 mmHg
  • a)
    0.8
  • b)
    0.6
  • c)
    0.4
  • d)
    0.2
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The vapour pressure of a solvent decreased by 10mmHg when a nonvolatil...
The equation governing the change in the vapor pressure when you use a nonvolatile liquid or solid is just a special case of Raoult's Law, Ptot = PaXa + PbXb. Since the second component has a negligible vapor pressure (nonvolatile), Raoult's law reduces to

P = P0X
where P is the vapor pressure of the mixture, P0 is the vapor pressure of the pure solvent and X is the mole fraction of the solvent.
Mole fraction of solute = 0.2
so mole fraction of solvent = 0.8 
So
P-10 = 0.8(P)
So P= 10/0.2 = 50
 
In second case
50-20 = x.50
30/50= x
So mole fraction of solvent = 0.6
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The vapour pressure of a solvent decreased by 10mmHg when a nonvolatile solute was added to the solvent. The mole fraction of the solute in the solutionis 0.2. What would be the mole fraction of the solvent if the decrease in the vapour pressure is to be 20 mmHga)0.8b)0.6c)0.4d)0.2Correct answer is option 'B'. Can you explain this answer?
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