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In which of the following compounds, nitrogen exhibits highest oxidation state?
- a)N3H
- b)NH2OH
- c)N2H4
- d)NH3
Correct answer is option 'A'. Can you explain this answer?
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In which of the following compounds, nitrogen exhibits highest oxidati...
so clearly N3H has the highest oxidation state
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In which of the following compounds, nitrogen exhibits highest oxidati...
Highest Oxidation State of Nitrogen
To determine the compound in which nitrogen exhibits the highest oxidation state, let's analyze each option:
a) N3H: In this compound, nitrogen is present in the +3 oxidation state. Each nitrogen atom is bonded to three hydrogen atoms, resulting in a total charge of +3.
b) NH2OH: In this compound, nitrogen is present in the +1 oxidation state. The oxygen atom is more electronegative than nitrogen and pulls the electron density towards itself, resulting in nitrogen having a lower oxidation state.
c) N2H4: In this compound, nitrogen is present in the -2 oxidation state. Each nitrogen atom is bonded to two hydrogen atoms, resulting in a total charge of -2.
d) NH3: In this compound, nitrogen is present in the -3 oxidation state. Each nitrogen atom is bonded to three hydrogen atoms, resulting in a total charge of -3.
Therefore, the compound in which nitrogen exhibits the highest oxidation state is N3H, which has nitrogen in the +3 oxidation state.
Explanation:
Nitrogen has a maximum of 5 valence electrons, and its oxidation state can range from -3 to +5. The oxidation state of an element is a measure of the degree of oxidation (loss of electrons) or reduction (gain of electrons) of that element in a chemical compound.
In N3H, nitrogen is bonded to three hydrogen atoms. Hydrogen has an oxidation state of +1, so the total charge contributed by the hydrogen atoms is +3. Since the compound as a whole is neutral, the nitrogen atom must have an oxidation state of +3 to balance the charge.
In NH2OH, the oxygen atom is more electronegative than nitrogen and pulls the electron density towards itself. As a result, the oxidation state of nitrogen decreases to +1. The oxygen atom has an oxidation state of -2, and the two hydrogen atoms have oxidation states of +1 each.
In N2H4, the nitrogen atoms are bonded to two hydrogen atoms each. Since hydrogen has an oxidation state of +1, the total charge contributed by the hydrogen atoms is +4. To balance the charge, each nitrogen atom must have an oxidation state of -2.
In NH3, the nitrogen atom is bonded to three hydrogen atoms. Again, hydrogen has an oxidation state of +1, so the total charge contributed by the hydrogen atoms is +3. To balance the charge, the nitrogen atom must have an oxidation state of -3.
Overall, the compound N3H has nitrogen in its highest oxidation state of +3.
To determine the compound in which nitrogen exhibits the highest oxidation state, let's analyze each option:
a) N3H: In this compound, nitrogen is present in the +3 oxidation state. Each nitrogen atom is bonded to three hydrogen atoms, resulting in a total charge of +3.
b) NH2OH: In this compound, nitrogen is present in the +1 oxidation state. The oxygen atom is more electronegative than nitrogen and pulls the electron density towards itself, resulting in nitrogen having a lower oxidation state.
c) N2H4: In this compound, nitrogen is present in the -2 oxidation state. Each nitrogen atom is bonded to two hydrogen atoms, resulting in a total charge of -2.
d) NH3: In this compound, nitrogen is present in the -3 oxidation state. Each nitrogen atom is bonded to three hydrogen atoms, resulting in a total charge of -3.
Therefore, the compound in which nitrogen exhibits the highest oxidation state is N3H, which has nitrogen in the +3 oxidation state.
Explanation:
Nitrogen has a maximum of 5 valence electrons, and its oxidation state can range from -3 to +5. The oxidation state of an element is a measure of the degree of oxidation (loss of electrons) or reduction (gain of electrons) of that element in a chemical compound.
In N3H, nitrogen is bonded to three hydrogen atoms. Hydrogen has an oxidation state of +1, so the total charge contributed by the hydrogen atoms is +3. Since the compound as a whole is neutral, the nitrogen atom must have an oxidation state of +3 to balance the charge.
In NH2OH, the oxygen atom is more electronegative than nitrogen and pulls the electron density towards itself. As a result, the oxidation state of nitrogen decreases to +1. The oxygen atom has an oxidation state of -2, and the two hydrogen atoms have oxidation states of +1 each.
In N2H4, the nitrogen atoms are bonded to two hydrogen atoms each. Since hydrogen has an oxidation state of +1, the total charge contributed by the hydrogen atoms is +4. To balance the charge, each nitrogen atom must have an oxidation state of -2.
In NH3, the nitrogen atom is bonded to three hydrogen atoms. Again, hydrogen has an oxidation state of +1, so the total charge contributed by the hydrogen atoms is +3. To balance the charge, the nitrogen atom must have an oxidation state of -3.
Overall, the compound N3H has nitrogen in its highest oxidation state of +3.
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Cement is the mixture of calcium (present in groups 2) and aluminium silicates (contains group 13 and 14 elements )
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In which of the following compounds, nitrogen exhibits highest oxidation state?a)N3Hb)NH2OHc)N2H4d)NH3Correct answer is option 'A'. Can you explain this answer?
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