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AB and CD are respectively the smallest and the longest sides of quadrilateral ABCD. Show that angel A > angel C?
Verified Answer
AB and CD are respectively the smallest and the longest sides of quadr...
In ΔABC, we have

BC > AB       

⇒ ∠BAC > ∠BCA  ...(1)

Similarly, in  ΔACD, we have

CD > AD       

⇒ ∠CAD > ∠ACD  ...(2)

On adding (1) and (2), we get

∠BAC + ∠CAD > ∠BCA + ∠ACD

⇒∠BAD > ∠BCD

⇒ ∠A > ∠C
Hence, it is proved that ∠A > ∠C 
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Most Upvoted Answer
AB and CD are respectively the smallest and the longest sides of quadr...
Given: 
In quadrilateral ABCD, AB smallest & CD is longest sides.

To Prove: ∠A>∠C 
& ∠B>∠D 

Construction: Join AC. 
Mark the angles as shown in the figure.. 

Proof:
In △ABC , AB is the shortest side. 

BC > AB 
∠2>∠4 …(i) 
[Angle opposite to longer side is greater] 

In △ADC , CD is the longest side 

CD > AD 
∠1>∠3 …(ii) 
[Angle opposite to longer side is greater] 

Adding (i) and (ii), we have 


∠2+∠1>∠4+∠3 
⇒∠A>∠C 

Similarly, by joining BD, we can prove that 
∠B>∠D 

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AB and CD are respectively the smallest and the longest sides of quadrilateral ABCD. Show that angel A > angel C?
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