Problem Analysis:
We are given that two men are carrying a uniform bar of length L on their shoulders. The bar is held horizontally such that the younger man gets 1/4th of the load. We need to determine the distance of the other man from that end.

Solution:

Let's assume that the younger man is carrying the load at the left end of the bar. We need to find the distance of the other man from the left end.

Step 1: Understanding the Given Information
- Two men are carrying a uniform bar on their shoulders.
- The bar is held horizontally.
- The younger man gets 1/4th of the load.
- The younger man is at the left end of the bar.

Step 2: Setting up the Problem
To solve this problem, we need to use the concept of moments. The moment of a force is the product of the force and the perpendicular distance from the line of action of the force to the reference point.

Let's consider the reference point as the left end of the bar where the younger man is located. We need to find the distance of the other man from this reference point.

Step 3: Calculating the Moments
The total moment about the reference point should be zero since the bar is in equilibrium. Let's calculate the moments of the forces acting on the bar.

- Moment of the force exerted by the younger man: This force is acting at the left end of the bar, so the moment is zero.

- Moment of the force exerted by the older man: Let's assume the distance of the older man from the reference point is x. Since the older man is carrying 3/4th of the load, the force exerted by him is 3/4 times the total load. The moment of this force is then (3/4) * (3/4) * L * x = (9/16) * L * x.

Since the total moment is zero, we have:

(9/16) * L * x = 0

Step 4: Solving for x
To find the distance of the older man from the reference point, we need to solve the equation:

(9/16) * L * x = 0

Since the product of two non-zero numbers is zero only when one of the numbers is zero, we can divide both sides of the equation by (9/16) * L to get:

x = 0

Therefore, the distance of the older man from the reference point (left end) is zero.

Step 5: Final Answer
The older man is carrying the load right next to the younger man at the left end of the bar. Hence, the distance of the older man from that end is zero.

In conclusion, if the younger man is at the end of the bar, the other man (older man) is right next to him at a distance of zero.

Net torque about centre of mass should be zero. Let the other man carry the load at a distance "a". Now,a x 3mg/4 = L/2 x mg/4 a = L/6