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A soil has liquid limit 65%, plastic limit of 30% and shrinkage limit of 25%, and it has natural moisture content of 45%. The liquidity index of soil is.

  • a) 
    1.5
  • b) 
    1.25
  • c) 
    0.6
  • d) 
    None of these.
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A soil has liquid limit 65%, plastic limit of 30% and shrinkage limit ...
Liquidity index = (water content-plastic limit)/(liquid limit-plastic limit).
= (45-30)/(65-30)
= 15/35
= 0.43
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Most Upvoted Answer
A soil has liquid limit 65%, plastic limit of 30% and shrinkage limit ...
Given information:
Liquid limit (LL) = 65%
Plastic limit (PL) = 30%
Shrinkage limit (SL) = 25%
Natural moisture content (NMC) = 45%

Liquidity Index (LI) = (NMC - PL) / (LL - PL)

Calculation:
LI = (45 - 30) / (65 - 30)
LI = 15 / 35
LI = 0.43

Therefore, the correct answer is option D (None of these), as the calculated LI value does not match any of the given options (1.5, 1.25 or 0.6).
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Community Answer
A soil has liquid limit 65%, plastic limit of 30% and shrinkage limit ...
Liquidity index=water content-plastic limit/liquid limit-plastic limit.
45-30/65-30=15/35=0.43
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A soil has liquid limit 65%, plastic limit of 30% and shrinkage limit of 25%, and it has natural moisture content of 45%. The liquidity index of soil is.a)1.5b)1.25c)0.6d)None of these.Correct answer is option 'D'. Can you explain this answer?
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