Civil Engineering (CE) Exam  >  Civil Engineering (CE) Questions  >  In a strained material, normal stresses on tw... Start Learning for Free
In a strained material, normal stresses on two mutually perpendicular planes are sx and sy (both a like) accompanied by a shear stress txy. One of the principal stresses will be zero, only it
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In a strained material, normal stresses on two mutually perpendicular ...
View all questions of this test
Explore Courses for Civil Engineering (CE) exam

Top Courses for Civil Engineering (CE)

In a strained material, normal stresses on two mutually perpendicular planes are sx and sy (both a like) accompanied by a shear stress txy. One of the principal stresses will be zero, only ita)b)c)d)Correct answer is option 'C'. Can you explain this answer?
Question Description
In a strained material, normal stresses on two mutually perpendicular planes are sx and sy (both a like) accompanied by a shear stress txy. One of the principal stresses will be zero, only ita)b)c)d)Correct answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about In a strained material, normal stresses on two mutually perpendicular planes are sx and sy (both a like) accompanied by a shear stress txy. One of the principal stresses will be zero, only ita)b)c)d)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a strained material, normal stresses on two mutually perpendicular planes are sx and sy (both a like) accompanied by a shear stress txy. One of the principal stresses will be zero, only ita)b)c)d)Correct answer is option 'C'. Can you explain this answer?.
Solutions for In a strained material, normal stresses on two mutually perpendicular planes are sx and sy (both a like) accompanied by a shear stress txy. One of the principal stresses will be zero, only ita)b)c)d)Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE). Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Here you can find the meaning of In a strained material, normal stresses on two mutually perpendicular planes are sx and sy (both a like) accompanied by a shear stress txy. One of the principal stresses will be zero, only ita)b)c)d)Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In a strained material, normal stresses on two mutually perpendicular planes are sx and sy (both a like) accompanied by a shear stress txy. One of the principal stresses will be zero, only ita)b)c)d)Correct answer is option 'C'. Can you explain this answer?, a detailed solution for In a strained material, normal stresses on two mutually perpendicular planes are sx and sy (both a like) accompanied by a shear stress txy. One of the principal stresses will be zero, only ita)b)c)d)Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of In a strained material, normal stresses on two mutually perpendicular planes are sx and sy (both a like) accompanied by a shear stress txy. One of the principal stresses will be zero, only ita)b)c)d)Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In a strained material, normal stresses on two mutually perpendicular planes are sx and sy (both a like) accompanied by a shear stress txy. One of the principal stresses will be zero, only ita)b)c)d)Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
Explore Courses for Civil Engineering (CE) exam

Top Courses for Civil Engineering (CE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev