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In the adjacent figure ABCD is a parallelogram ABEF is a rectangle show that ∆AFD congruent to ∆BEC?
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Understanding the Configuration
In the given configuration, we have a parallelogram ABCD and a rectangle ABEF. We need to show that triangles AFD and BEC are congruent.
Identifying Key Points
- Parallelogram Properties:
- Opposite sides are equal: AB = CD and AD = BC.
- Opposite angles are equal: ∠A = ∠C and ∠B = ∠D.
- Rectangle Properties:
- All angles are right angles: ∠ABE = ∠BAE = ∠EAF = ∠FEA = 90 degrees.
- Opposite sides are equal: AB = EF and AE = BF.
Triangles to Compare
- Triangle AFD:
- Vertices: A, F, D.
- Contains one right angle at F (since ABEF is a rectangle).
- Triangle BEC:
- Vertices: B, E, C.
- Also contains one right angle at E (since ABEF is a rectangle).
Proving Congruence
- Side Lengths:
- AF = BE (since both are sides of the rectangle).
- AD = BC (opposite sides of the parallelogram).
- Shared Side:
- The side FD is common to both triangles.
- Angle Criteria:
- ∠AFD = ∠BEC (both are right angles).
Conclusion
Using the Side-Angle-Side (SAS) Congruence Postulate:
1. AF = BE (equal sides).
2. FD is common.
3. ∠AFD = ∠BEC (both are right angles).
Thus, triangles AFD and BEC are congruent. This demonstrates that the properties of both the parallelogram and rectangle facilitate the congruence of the triangles, confirming the relationship effectively.
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In the adjacent figure ABCD is a parallelogram ABEF is a rectangle show that ∆AFD congruent to ∆BEC?
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