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The amount of ZnO produced when 195 gm of ZnS reacts with 89.6 L O2 at 1 atm, and 273 K is 32.6 P gm. Find the value of P.
    Correct answer is '5'. Can you explain this answer?
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    The amount of ZnO produced when 195 gm of ZnS reacts with 89.6 LO2 at ...
    195gm of ZnS means 2 moles of ZnS while 89.6L of O2 means 4 mole of O2; so ZnS become the limiting factor.So,2ZnS + 3O2 gives 2 ZnO + 2SO2
    So, 2 moles of ZnO means 162g and acc to equation162÷32.6≈ 5
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    The amount of ZnO produced when 195 gm of ZnS reacts with 89.6 LO2 at 1 atm, and 273 K is 32.6 P gm. Find the value of P.Correct answer is '5'. Can you explain this answer?
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    The amount of ZnO produced when 195 gm of ZnS reacts with 89.6 LO2 at 1 atm, and 273 K is 32.6 P gm. Find the value of P.Correct answer is '5'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The amount of ZnO produced when 195 gm of ZnS reacts with 89.6 LO2 at 1 atm, and 273 K is 32.6 P gm. Find the value of P.Correct answer is '5'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The amount of ZnO produced when 195 gm of ZnS reacts with 89.6 LO2 at 1 atm, and 273 K is 32.6 P gm. Find the value of P.Correct answer is '5'. Can you explain this answer?.
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