IIT JAM Exam > IIT JAM Questions > In an experiment, 200 ml of 0.5 M oxalic acid...
Start Learning for Free
In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption 
is 0.06 p. Find the value of p.
is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of a...
No. of moles of oxalic acid= molarity * volume. = 0.1
no. of moles of oxalic acid = given mass ÷ molar mass
0.1= given mass ÷ 90g
So, given mass= 9g
no. of moles after adsorption= 0.4
given mass= 7.2g
amount of adsorbate= 9.0 - 7.2 g=1.8g &
x÷m= 1.8÷10*0.06= 3=p
no. of moles of oxalic acid = given mass ÷ molar mass
0.1= given mass ÷ 90g
So, given mass= 9g
no. of moles after adsorption= 0.4
given mass= 7.2g
amount of adsorbate= 9.0 - 7.2 g=1.8g &
x÷m= 1.8÷10*0.06= 3=p
|
Explore Courses for IIT JAM exam
|
|
Similar IIT JAM Doubts
In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer?
Question Description
In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer?.
In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer?.
Solutions for In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM.
Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.
Here you can find the meaning of In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer?, a detailed solution for In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer? has been provided alongside types of In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In an experiment, 200 ml of 0.5 M oxalic acid is shaken with 10 g of activated charcoal and filtered. The concentration of the filtrate is reduced to 0.4 M. The amount of adsorption is 0.06 p. Find the value of p.Correct answer is '3'. Can you explain this answer? tests, examples and also practice IIT JAM tests.
|
|
Explore Courses for IIT JAM exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup