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Osmotic pressure of insulin solution at 298 K is found to be 0.0072 atm at 298 K. Hence, height of water column due to this pressure is (density of mercury = 13.6 g mL-1)
- a)0.76 cm
- b)0.70 cm
- c)7.44 cm
- d)76 cm
Correct answer is option 'C'. Can you explain this answer?
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Osmotic pressure of insulin solution at 298 K is found to be 0.0072 at...
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Osmotic pressure of insulin solution at 298 K is found to be 0.0072 at...
Given:
Osmotic pressure of insulin solution at 298 K = 0.0072 atm
Density of mercury = 13.6 g/mL
To find:
Height of water column due to this pressure
Formula:
The height of a liquid column due to a pressure difference can be calculated using the equation:
h = (P * d * g) / (ρ * g)
where,
h = height of the liquid column
P = pressure difference
d = density of the liquid
g = acceleration due to gravity
ρ = density of the fluid
Calculation:
Given that the osmotic pressure of the insulin solution is 0.0072 atm, we can convert it to units of cm of Hg (mercury) using the conversion factor:
1 atm = 76 cm Hg (approximately)
So, the osmotic pressure of the insulin solution in cm Hg is:
0.0072 atm * 76 cm Hg/atm = 0.5472 cm Hg
Now, we can calculate the height of the water column using the formula:
h = (P * d * g) / (ρ * g)
Substituting the values:
h = (0.5472 cm Hg * 13.6 g/mL * 9.8 m/s^2) / (1 g/cm^3 * 9.8 m/s^2)
Simplifying the equation:
h = (0.5472 cm Hg * 13.6 g/mL) / (1 g/cm^3) = 7.4432 cm
The height of the water column due to the osmotic pressure of the insulin solution is approximately 7.44 cm.
Therefore, the correct answer is option C) 7.44 cm.
Osmotic pressure of insulin solution at 298 K = 0.0072 atm
Density of mercury = 13.6 g/mL
To find:
Height of water column due to this pressure
Formula:
The height of a liquid column due to a pressure difference can be calculated using the equation:
h = (P * d * g) / (ρ * g)
where,
h = height of the liquid column
P = pressure difference
d = density of the liquid
g = acceleration due to gravity
ρ = density of the fluid
Calculation:
Given that the osmotic pressure of the insulin solution is 0.0072 atm, we can convert it to units of cm of Hg (mercury) using the conversion factor:
1 atm = 76 cm Hg (approximately)
So, the osmotic pressure of the insulin solution in cm Hg is:
0.0072 atm * 76 cm Hg/atm = 0.5472 cm Hg
Now, we can calculate the height of the water column using the formula:
h = (P * d * g) / (ρ * g)
Substituting the values:
h = (0.5472 cm Hg * 13.6 g/mL * 9.8 m/s^2) / (1 g/cm^3 * 9.8 m/s^2)
Simplifying the equation:
h = (0.5472 cm Hg * 13.6 g/mL) / (1 g/cm^3) = 7.4432 cm
The height of the water column due to the osmotic pressure of the insulin solution is approximately 7.44 cm.
Therefore, the correct answer is option C) 7.44 cm.
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Osmotic pressure of insulin solution at 298 K is found to be 0.0072 atm at 298 K. Hence, height of water column due to this pressure is (density of mercury = 13.6 g mL-1)a)0.76 cmb)0.70cmc)7.44cmd)76cmCorrect answer is option 'C'. Can you explain this answer?
Question Description
Osmotic pressure of insulin solution at 298 K is found to be 0.0072 atm at 298 K. Hence, height of water column due to this pressure is (density of mercury = 13.6 g mL-1)a)0.76 cmb)0.70cmc)7.44cmd)76cmCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Osmotic pressure of insulin solution at 298 K is found to be 0.0072 atm at 298 K. Hence, height of water column due to this pressure is (density of mercury = 13.6 g mL-1)a)0.76 cmb)0.70cmc)7.44cmd)76cmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Osmotic pressure of insulin solution at 298 K is found to be 0.0072 atm at 298 K. Hence, height of water column due to this pressure is (density of mercury = 13.6 g mL-1)a)0.76 cmb)0.70cmc)7.44cmd)76cmCorrect answer is option 'C'. Can you explain this answer?.
Osmotic pressure of insulin solution at 298 K is found to be 0.0072 atm at 298 K. Hence, height of water column due to this pressure is (density of mercury = 13.6 g mL-1)a)0.76 cmb)0.70cmc)7.44cmd)76cmCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Osmotic pressure of insulin solution at 298 K is found to be 0.0072 atm at 298 K. Hence, height of water column due to this pressure is (density of mercury = 13.6 g mL-1)a)0.76 cmb)0.70cmc)7.44cmd)76cmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Osmotic pressure of insulin solution at 298 K is found to be 0.0072 atm at 298 K. Hence, height of water column due to this pressure is (density of mercury = 13.6 g mL-1)a)0.76 cmb)0.70cmc)7.44cmd)76cmCorrect answer is option 'C'. Can you explain this answer?.
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Osmotic pressure of insulin solution at 298 K is found to be 0.0072 atm at 298 K. Hence, height of water column due to this pressure is (density of mercury = 13.6 g mL-1)a)0.76 cmb)0.70cmc)7.44cmd)76cmCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Osmotic pressure of insulin solution at 298 K is found to be 0.0072 atm at 298 K. Hence, height of water column due to this pressure is (density of mercury = 13.6 g mL-1)a)0.76 cmb)0.70cmc)7.44cmd)76cmCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Osmotic pressure of insulin solution at 298 K is found to be 0.0072 atm at 298 K. Hence, height of water column due to this pressure is (density of mercury = 13.6 g mL-1)a)0.76 cmb)0.70cmc)7.44cmd)76cmCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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