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40%of PCL5 is not dissociated at 300C .The reaction is carried out at flask of 1L capacity. the value of Kc would be??? 1) 3.2. 2)1.6. 3) (3.2)^-1. 4)0.9 the correct ans is 4. CAN ANY ONE EXPLAIN HOW?
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40%of PCL5 is not dissociated at 300C .The reaction is carried out at ...
Dissociation of PCl5 can be written as :
Here given that, PCl5 <--> PCl3 + Cl2
Initially, concn., 1 mol..0....0
At equilibrium, 1-x...x...x
Kc =[PCl3 ][Cl2] / [PCl5 ]...(1)
% age of dissociation = 60 %
Let the number of moles of PCl5 started with = 1 mol
Then there is dissocitiation of 0.6 mol of PCl5
At Equilibrium PCl5 = 0.4 mol (1- 0.6) , PCl3 = 0.6 mol and Cl2 = 0.6 mol
Putting the values in Eq (1)
Kc = 0.6 mol x 0.6 mol / 0.4 mol
= 0.9
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40%of PCL5 is not dissociated at 300C .The reaction is carried out at ...
The given problem states that 40% of PCl5 is not dissociated at 300°C. Let's assume that x is the amount of PCl5 that dissociates. Therefore, the initial amount of PCl5 in the flask is 1 - x.
To find the value of Kc, we need to set up the equilibrium expression for the dissociation of PCl5:
PCl5 ⇌ PCl3 + Cl2
The equilibrium constant expression for this reaction is:
Kc = [PCl3][Cl2] / [PCl5]
We can express the concentrations of PCl3 and Cl2 in terms of x, as they are the products of the dissociation reaction:
[PCl3] = x
[Cl2] = x
The concentration of PCl5 at equilibrium can be expressed as:
[PCl5] = 1 - x
Substituting these values into the equilibrium constant expression, we get:
Kc = (x * x) / (1 - x)
Since we know that 40% of PCl5 is not dissociated, we can write:
(1 - x) = 0.4
Solving for x, we find:
x = 0.6
Substituting this value of x into the equilibrium constant expression, we get:
Kc = (0.6 * 0.6) / (1 - 0.6)
= 0.36 / 0.4
= 0.9
Therefore, the value of Kc is 0.9. Option 4 is the correct answer.
In summary:
- Assume x is the amount of PCl5 that dissociates.
- Set up the equilibrium constant expression using the concentrations of the products and reactant.
- Substitute the given information that 40% of PCl5 is not dissociated.
- Solve for x.
- Substitute the value of x into the equilibrium constant expression to find Kc.
- The correct answer is option 4, Kc = 0.9.
To find the value of Kc, we need to set up the equilibrium expression for the dissociation of PCl5:
PCl5 ⇌ PCl3 + Cl2
The equilibrium constant expression for this reaction is:
Kc = [PCl3][Cl2] / [PCl5]
We can express the concentrations of PCl3 and Cl2 in terms of x, as they are the products of the dissociation reaction:
[PCl3] = x
[Cl2] = x
The concentration of PCl5 at equilibrium can be expressed as:
[PCl5] = 1 - x
Substituting these values into the equilibrium constant expression, we get:
Kc = (x * x) / (1 - x)
Since we know that 40% of PCl5 is not dissociated, we can write:
(1 - x) = 0.4
Solving for x, we find:
x = 0.6
Substituting this value of x into the equilibrium constant expression, we get:
Kc = (0.6 * 0.6) / (1 - 0.6)
= 0.36 / 0.4
= 0.9
Therefore, the value of Kc is 0.9. Option 4 is the correct answer.
In summary:
- Assume x is the amount of PCl5 that dissociates.
- Set up the equilibrium constant expression using the concentrations of the products and reactant.
- Substitute the given information that 40% of PCl5 is not dissociated.
- Solve for x.
- Substitute the value of x into the equilibrium constant expression to find Kc.
- The correct answer is option 4, Kc = 0.9.
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40%of PCL5 is not dissociated at 300C .The reaction is carried out at flask of 1L capacity. the value of Kc would be??? 1) 3.2. 2)1.6. 3) (3.2)^-1. 4)0.9 the correct ans is 4. CAN ANY ONE EXPLAIN HOW?
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40%of PCL5 is not dissociated at 300C .The reaction is carried out at flask of 1L capacity. the value of Kc would be??? 1) 3.2. 2)1.6. 3) (3.2)^-1. 4)0.9 the correct ans is 4. CAN ANY ONE EXPLAIN HOW? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 40%of PCL5 is not dissociated at 300C .The reaction is carried out at flask of 1L capacity. the value of Kc would be??? 1) 3.2. 2)1.6. 3) (3.2)^-1. 4)0.9 the correct ans is 4. CAN ANY ONE EXPLAIN HOW? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 40%of PCL5 is not dissociated at 300C .The reaction is carried out at flask of 1L capacity. the value of Kc would be??? 1) 3.2. 2)1.6. 3) (3.2)^-1. 4)0.9 the correct ans is 4. CAN ANY ONE EXPLAIN HOW?.
40%of PCL5 is not dissociated at 300C .The reaction is carried out at flask of 1L capacity. the value of Kc would be??? 1) 3.2. 2)1.6. 3) (3.2)^-1. 4)0.9 the correct ans is 4. CAN ANY ONE EXPLAIN HOW? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 40%of PCL5 is not dissociated at 300C .The reaction is carried out at flask of 1L capacity. the value of Kc would be??? 1) 3.2. 2)1.6. 3) (3.2)^-1. 4)0.9 the correct ans is 4. CAN ANY ONE EXPLAIN HOW? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 40%of PCL5 is not dissociated at 300C .The reaction is carried out at flask of 1L capacity. the value of Kc would be??? 1) 3.2. 2)1.6. 3) (3.2)^-1. 4)0.9 the correct ans is 4. CAN ANY ONE EXPLAIN HOW?.
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