Prove that the bisectors of the angles of a linear pair are at right a...
In the figure ∠ACD and ∠BCD form a linear pair ⇒∠ACD+∠BCD=180degree
CE and CF bisect ∠ACD and ∠BCD respectively
∠ACD+∠BCD=180degree
⇒∠ACD/2 + ∠BCD/2 = 90degree
⇒∠ECD + ∠DCF = 90degree as CE and CF bisect ∠ACD and ∠BCD respectively
⇒∠ECF = 90degree (∠ECD + ∠DCF = ∠ECF)
∠ECF is the angle between CE and CF which bisect the linear pair of angles ∠ACD and ∠BCD
Hence proved that the angle bisectors of a linear pair are at right angles to each other
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Prove that the bisectors of the angles of a linear pair are at right a...
Proof that the bisectors of the angles of a linear pair are at right angles:
To prove that the bisectors of the angles of a linear pair are at right angles, we need to understand the properties of a linear pair and angle bisectors.
Linear Pair:
A linear pair is formed when two adjacent angles are supplementary, meaning their sum is equal to 180 degrees. In a linear pair, the angles share a common vertex and a common side, while their other sides form a straight line.
Angle Bisectors:
An angle bisector is a line or ray that divides an angle into two equal parts. It cuts the angle into two congruent angles. The angle bisector intersects the angle at its vertex.
Proof:
Step 1: Let there be a linear pair with two adjacent angles, ∠PQR and ∠RQS, sharing a common side QR.
Step 2: Assume that the bisector of ∠PQR is line AB, and the bisector of ∠RQS is line CD.
Step 3: As per the definition of an angle bisector, line AB divides ∠PQR into two equal angles, ∠PQA and ∠AQR. Similarly, line CD divides ∠RQS into two equal angles, ∠RQC and ∠CQS.
Step 4: Since line AB is the bisector of ∠PQR, it divides the angle into two congruent angles, ∠PQA and ∠AQR.
Step 5: Similarly, line CD is the bisector of ∠RQS and divides the angle into two congruent angles, ∠RQC and ∠CQS.
Step 6: Now, we can see that ∠PQA ≅ ∠CQS and ∠AQR ≅ ∠RQC. This is because the bisectors divide the angles into congruent parts.
Step 7: According to the definition of congruent angles, if two angles are congruent, their measures are equal.
Step 8: Therefore, we can conclude that ∠PQA = ∠CQS and ∠AQR = ∠RQC.
Step 9: By combining these two equalities, we get ∠PQA + ∠AQR = ∠CQS + ∠RQC.
Step 10: Since ∠PQR and ∠RQS are supplementary angles in a linear pair, their sum is equal to 180 degrees. Therefore, ∠PQR + ∠RQS = 180 degrees.
Step 11: By substituting the values from Step 9 and Step 10, we have 180 degrees = ∠CQS + ∠RQC.
Step 12: We can rearrange the equation to get ∠CQS + ∠RQC = 180 degrees.
Step 13: This equation shows that the sum of ∠CQS and ∠RQC is equal to 180 degrees, which proves that they are supplementary angles.
Step 14: By the definition of supplementary angles,
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