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Two gas samples were analysed, one of them contains 1.2 g of C and 3.2 g of O. The other contained 27.3% Cm and 72.72% of O approximately. The experiment data are in accord with
- a)Law of definite proportions
- b)Law of conservation of mass
- c)Law of multiple proportions
- d)Law of reciprocal proportions
Correct answer is option 'A'. Can you explain this answer?
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Two gas samples were analysed, one of them contains 1.2 g of C and 3.2...
Law of Definite Proportions
The discovery that mass was always conserved in chemical reactions was soon followed by the law of definite proportions, which states that a given chemical compound always contains the same elements in the exact same proportions by mass. As an example, any sample of pure water contains 11.19% hydrogen and 88.81% oxygen by mass. It does not matter where the sample of water came from or how it was prepared. Its composition, like that of every other compound, is fixed.
Another example is carbon dioxide. This gas is produced from a variety of reactions, often by the burning of materials. The structure of the gas consists of one atom of carbon and two atoms of oxygen. Carbon dioxide production is of interest in many areas, from the amount we breathe to the amount of the gas produced by burning wood or fossil fuels. By knowing the exact composition of carbon dioxide, we can make predictions as to the effects of different chemical processes.
Most Upvoted Answer
Two gas samples were analysed, one of them contains 1.2 g of C and 3.2...
**Introduction:**
The question states that two gas samples were analyzed, and their composition is provided. The aim is to determine which scientific law is in accord with the experiment data.
**Explanation:**
To determine which scientific law is in accord with the experiment data, we need to analyze the composition of the two gas samples and compare it with the known laws of chemistry.
1. **Law of Definite Proportions:**
According to the Law of Definite Proportions, a chemical compound always contains the same elements in the same proportion by mass. In other words, the ratio of the masses of the elements in a compound is always constant.
2. **Law of Conservation of Mass:**
The Law of Conservation of Mass states that mass is neither created nor destroyed in a chemical reaction. In other words, the total mass of the reactants is equal to the total mass of the products.
3. **Law of Multiple Proportions:**
The Law of Multiple Proportions states that when two elements combine to form different compounds, the ratio of the masses of one element that combines with a fixed mass of the other element can be expressed in small whole numbers.
4. **Law of Reciprocal Proportions:**
The Law of Reciprocal Proportions states that if two elements can combine to form more than one compound, the masses of one element that combine with a fixed mass of the second element are in the ratio of small whole numbers.
**Analysis:**
- Let's analyze the composition of the first gas sample, which contains 1.2 g of C and 3.2 g of O. The ratio of the masses of C to O in this sample is 1.2:3.2, which can be simplified to 0.375:1.
- Now, let's analyze the composition of the second gas sample, which contains 27.3% C and 72.72% O. The ratio of the masses of C to O in this sample can be calculated as follows:
- Assume we have 100 g of the sample.
- Then, the mass of C in the sample would be 27.3 g (27.3% of 100 g).
- Similarly, the mass of O in the sample would be 72.72 g (72.72% of 100 g).
- The ratio of the masses of C to O in this sample is 27.3:72.72, which can be simplified to 0.375:1.
**Conclusion:**
The ratios of the masses of C to O in both gas samples are the same, which is 0.375:1. This is in accordance with the Law of Definite Proportions, which states that a chemical compound always contains the same elements in the same proportion by mass. Therefore, the correct answer is option 'A' - Law of Definite Proportions.
The question states that two gas samples were analyzed, and their composition is provided. The aim is to determine which scientific law is in accord with the experiment data.
**Explanation:**
To determine which scientific law is in accord with the experiment data, we need to analyze the composition of the two gas samples and compare it with the known laws of chemistry.
1. **Law of Definite Proportions:**
According to the Law of Definite Proportions, a chemical compound always contains the same elements in the same proportion by mass. In other words, the ratio of the masses of the elements in a compound is always constant.
2. **Law of Conservation of Mass:**
The Law of Conservation of Mass states that mass is neither created nor destroyed in a chemical reaction. In other words, the total mass of the reactants is equal to the total mass of the products.
3. **Law of Multiple Proportions:**
The Law of Multiple Proportions states that when two elements combine to form different compounds, the ratio of the masses of one element that combines with a fixed mass of the other element can be expressed in small whole numbers.
4. **Law of Reciprocal Proportions:**
The Law of Reciprocal Proportions states that if two elements can combine to form more than one compound, the masses of one element that combine with a fixed mass of the second element are in the ratio of small whole numbers.
**Analysis:**
- Let's analyze the composition of the first gas sample, which contains 1.2 g of C and 3.2 g of O. The ratio of the masses of C to O in this sample is 1.2:3.2, which can be simplified to 0.375:1.
- Now, let's analyze the composition of the second gas sample, which contains 27.3% C and 72.72% O. The ratio of the masses of C to O in this sample can be calculated as follows:
- Assume we have 100 g of the sample.
- Then, the mass of C in the sample would be 27.3 g (27.3% of 100 g).
- Similarly, the mass of O in the sample would be 72.72 g (72.72% of 100 g).
- The ratio of the masses of C to O in this sample is 27.3:72.72, which can be simplified to 0.375:1.
**Conclusion:**
The ratios of the masses of C to O in both gas samples are the same, which is 0.375:1. This is in accordance with the Law of Definite Proportions, which states that a chemical compound always contains the same elements in the same proportion by mass. Therefore, the correct answer is option 'A' - Law of Definite Proportions.
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Two gas samples were analysed, one of them contains 1.2 g of C and 3.2...
A)Law of definite proportions
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Two gas samples were analysed, one of them contains 1.2 g of C and 3.2 g of O. The other contained 27.3% Cm and 72.72% of O approximately. The experiment data are in accord witha)Law of definite proportionsb)Law of conservation of massc)Law of multiple proportionsd)Law of reciprocal proportionsCorrect answer is option 'A'. Can you explain this answer?
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Two gas samples were analysed, one of them contains 1.2 g of C and 3.2 g of O. The other contained 27.3% Cm and 72.72% of O approximately. The experiment data are in accord witha)Law of definite proportionsb)Law of conservation of massc)Law of multiple proportionsd)Law of reciprocal proportionsCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two gas samples were analysed, one of them contains 1.2 g of C and 3.2 g of O. The other contained 27.3% Cm and 72.72% of O approximately. The experiment data are in accord witha)Law of definite proportionsb)Law of conservation of massc)Law of multiple proportionsd)Law of reciprocal proportionsCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two gas samples were analysed, one of them contains 1.2 g of C and 3.2 g of O. The other contained 27.3% Cm and 72.72% of O approximately. The experiment data are in accord witha)Law of definite proportionsb)Law of conservation of massc)Law of multiple proportionsd)Law of reciprocal proportionsCorrect answer is option 'A'. Can you explain this answer?.
Two gas samples were analysed, one of them contains 1.2 g of C and 3.2 g of O. The other contained 27.3% Cm and 72.72% of O approximately. The experiment data are in accord witha)Law of definite proportionsb)Law of conservation of massc)Law of multiple proportionsd)Law of reciprocal proportionsCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Two gas samples were analysed, one of them contains 1.2 g of C and 3.2 g of O. The other contained 27.3% Cm and 72.72% of O approximately. The experiment data are in accord witha)Law of definite proportionsb)Law of conservation of massc)Law of multiple proportionsd)Law of reciprocal proportionsCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two gas samples were analysed, one of them contains 1.2 g of C and 3.2 g of O. The other contained 27.3% Cm and 72.72% of O approximately. The experiment data are in accord witha)Law of definite proportionsb)Law of conservation of massc)Law of multiple proportionsd)Law of reciprocal proportionsCorrect answer is option 'A'. Can you explain this answer?.
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Two gas samples were analysed, one of them contains 1.2 g of C and 3.2 g of O. The other contained 27.3% Cm and 72.72% of O approximately. The experiment data are in accord witha)Law of definite proportionsb)Law of conservation of massc)Law of multiple proportionsd)Law of reciprocal proportionsCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Two gas samples were analysed, one of them contains 1.2 g of C and 3.2 g of O. The other contained 27.3% Cm and 72.72% of O approximately. The experiment data are in accord witha)Law of definite proportionsb)Law of conservation of massc)Law of multiple proportionsd)Law of reciprocal proportionsCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Two gas samples were analysed, one of them contains 1.2 g of C and 3.2 g of O. The other contained 27.3% Cm and 72.72% of O approximately. The experiment data are in accord witha)Law of definite proportionsb)Law of conservation of massc)Law of multiple proportionsd)Law of reciprocal proportionsCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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