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An object is placed at a distance of 10cm from a concave mirror of radius of curvature 40cm. find the nature,position and magnitude of the image.?
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An object is placed at a distance of 10cm from a concave mirror of rad...
Given:
- Object distance (u) = 10 cm
- Radius of curvature (R) = -40 cm (negative sign indicates concave mirror)

Formula:
The mirror formula is given by:
1/f = 1/v - 1/u
Where,
f = focal length
v = image distance

Calculating Focal Length:
Using the mirror formula, we can rearrange the equation as:
1/v = 1/f + 1/u
1/v = 1/f - 1/10

Since the mirror is concave, the focal length is negative. Let's substitute the values and solve for v:
1/v = 1/f - 1/10
1/v = -1/40 - 1/10
1/v = -5/40 - 4/40
1/v = -9/40
v = -40/9 cm

Determining the Position of the Image:
The image distance (v) is negative, which means the image is formed on the same side as the object. Therefore, the image is real and formed in front of the mirror.

Calculating the Magnitude of the Image:
The magnification (m) of the image is given by:
m = -v/u

Substituting the given values:
m = -(-40/9)/10
m = 4/9

Since the magnification is positive, it indicates an upright image.

Summary:
- The nature of the image is real and inverted.
- The position of the image is -40/9 cm from the mirror.
- The magnitude of the image is 4/9, indicating an upright image.

Therefore, based on the given information, the image formed by the concave mirror is real, inverted, and located at a distance of -40/9 cm from the mirror with a magnification of 4/9.
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An object is placed at a distance of 10cm from a concave mirror of radius of curvature 40cm. find the nature,position and magnitude of the image.?
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