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A wooden cylinder of sp.gr. = 0.6 and circular in cross-section is required to float in oil(sp.gr. = 0.90). Find the L/D ratio for the cylinder to float with its longitudinal axis vertical in oil, where L is the height of cylinder and D is its diameter.

  • a) 
    L/D<9/16
  • b) 
    L/D<3/4
  • c) 
    L/D<2/3
  • d) 
    None of the mentioned
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A wooden cylinder of sp.gr. = 0.6 and circular in cross-section is req...
By principle of buoyancy,
Weight of cylinder = Weight of water displaced
h=2L/3
AG=L/2
AB=L/3
BG=AG-AB=L/6
GM= Metacentric height=I/∀ – BG=3D2/32L-L/6
For stable equilibrium, GM should be positive
GM>0
i.e L/D<3/4.
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Most Upvoted Answer
A wooden cylinder of sp.gr. = 0.6 and circular in cross-section is req...
= 2.25

To float with its longitudinal axis vertical, the weight of the cylinder should be equal to the weight of the displaced oil. Let the diameter of the cylinder be D and its height be L. Then, the volume of the cylinder is πD^2L/4 and its weight is (πD^2L/4) × 0.6g, where g is the acceleration due to gravity.

The weight of the displaced oil is (πD^2L/4) × (0.9-1)g = -(πD^2L/4) × 0.1g, as the weight of the displaced oil is equal to the weight of the cylinder.

Equating the two weights, we get:

(πD^2L/4) × 0.6g = -(πD^2L/4) × 0.1g

Simplifying, we get:

D^2/L = 2.25

Therefore, the L/D ratio for the cylinder to float with its longitudinal axis vertical in oil is 2.25.
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A wooden cylinder of sp.gr. = 0.6 and circular in cross-section is req...
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A wooden cylinder of sp.gr. = 0.6 and circular in cross-section is required to float in oil(sp.gr. = 0.90). Find the L/D ratio for the cylinder to float with its longitudinal axis vertical in oil, where L is the height of cylinder and D is its diameter.a)L/D<9/16b)L/D<3/4c)L/D<2/3d)None of the mentionedCorrect answer is option 'B'. Can you explain this answer?
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