An electron is found in an orbital with one radial node and two angula...
You will have observed that the total number of nodes is equal to the principal quantum number, n, minus one. In other words, the 1s has 0 nodes the 2s and the 2p orbitals each have 1 node the 3s, 3p and 3d orbitals each have 2 nodes the 4s, 4p, 4d, and 4f orbitals each have 3 nodes and so on.
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An electron is found in an orbital with one radial node and two angula...
Explanation:
The given information about the electron is that it is found in an orbital with one radial node and two angular nodes. This information can be used to determine the type of orbital the electron is in.
1. Radial Nodes:
Radial nodes are the points in the orbital where the probability of finding an electron is zero. The number of radial nodes in an orbital is equal to the principal quantum number (n) minus the angular momentum quantum number (l) minus 1. In this case, we are given that there is one radial node.
2. Angular Nodes:
Angular nodes are the planes in the orbital where the probability of finding an electron is zero. The number of angular nodes in an orbital is equal to the angular momentum quantum number (l). In this case, we are given that there are two angular nodes.
3. Determining the Type of Orbital:
Using the information about the number of radial and angular nodes, we can determine the type of orbital the electron is in. The types of orbitals are named using the following notation:
n, l
- n represents the principal quantum number
- l represents the angular momentum quantum number
The possible orbitals for the given electron are:
- 1s
- 2s, 2p
- 3s, 3p, 3d
- 4s, 4p, 4d, 4f
The orbital with one radial node and two angular nodes is 4d. Therefore, the correct answer is A) 4d.
An electron is found in an orbital with one radial node and two angula...
The Total no. Of nodes in an orbital = (n - 1)So in 4d orbital,
n=4, l=2 hence
No. of nodes= 4-1 = 3
No. of radial nodes in an orbital = (n - l - 1)
So, no. of nodes in 4d = 4-2-1=1
Since, no. Of angular nodes = l
=2
Hence the option d) i.e., 4d is correct.