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If √m √n-√p=0,then find the value of(m n-p)^2?
Verified Answer
If √m √n-√p=0,then find the value of(m n-p)^2?
√m+√n-√p = 0
=> √m+√n = √p

squaring both sides

(√m+√n)^2 = (√p)^2
=> (√m)^2+(√n)^2+2(√m)(√n) = p
=> m+n+2√mn = p

=> m+n-p = -2√mn

(m+n-p)^2 = (-2√mn)^2
BY SQUARING BOTH SIDES


=> (m+n-p)^2 = 4mn
This question is part of UPSC exam. View all Class 9 courses
Most Upvoted Answer
If √m √n-√p=0,then find the value of(m n-p)^2?
Given m+n=p
square both sides : m+n+2 [mn] =p
so ,m+n-p 2 (mn)
square
Community Answer
If √m √n-√p=0,then find the value of(m n-p)^2?
Given  √m + √n = √p

Square both sides:m + n + 2√(mn) = p

So,m+n- p = - 2√(mn)

So, (m + n - p)raised to the power 2 = 4 mn
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