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For a given base voltage and base volt-amp, the per unit impedance value of an element is X. What will be the per-unit impedance value of this element when the voltage and volt-amp bases are both doubled
- a)4 X
- b)2 X
- c)X
- d)0.5 X
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
For a given base voltage and base volt-amp, the per unit impedance val...
Explanation:
Given data:
- Base voltage = Vb
- Base volt-amp = Sb
- Per unit impedance value = X
Per unit impedance is defined as the ratio of actual impedance to the base impedance. Therefore, the actual impedance of the element is:
Z = X * Vb^2 / Sb
When the voltage and volt-amp bases are both doubled, the new values become:
- New base voltage = 2Vb
- New base volt-amp = 2Sb
Using these new values, the new actual impedance of the element can be calculated as:
Z' = X * (2Vb)^2 / (2Sb)
Z' = X * Vb^2 / Sb
Z' = X
Therefore, the per unit impedance value remains the same when the voltage and volt-amp bases are both doubled. It does not change, and it is still X.
Hence, the correct answer is option D, i.e., 0.5 X.
Given data:
- Base voltage = Vb
- Base volt-amp = Sb
- Per unit impedance value = X
Per unit impedance is defined as the ratio of actual impedance to the base impedance. Therefore, the actual impedance of the element is:
Z = X * Vb^2 / Sb
When the voltage and volt-amp bases are both doubled, the new values become:
- New base voltage = 2Vb
- New base volt-amp = 2Sb
Using these new values, the new actual impedance of the element can be calculated as:
Z' = X * (2Vb)^2 / (2Sb)
Z' = X * Vb^2 / Sb
Z' = X
Therefore, the per unit impedance value remains the same when the voltage and volt-amp bases are both doubled. It does not change, and it is still X.
Hence, the correct answer is option D, i.e., 0.5 X.
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Community Answer
For a given base voltage and base volt-amp, the per unit impedance val...
It would same X.....
Per unit value = actual value / base value
If we double the base value definitely per unit value would be half of the pervious value.. but here we are talking about impedance which is euqals to V/I.
So if we V and I both are getting divided by 2 then ratio would be same.. that's impedance would remain same.
Per unit value = actual value / base value
If we double the base value definitely per unit value would be half of the pervious value.. but here we are talking about impedance which is euqals to V/I.
So if we V and I both are getting divided by 2 then ratio would be same.. that's impedance would remain same.
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For a given base voltage and base volt-amp, the per unit impedance value of an element is X. What will be the per-unit impedance value of this element when the voltage and volt-amp bases are both doubleda)4 Xb)2 Xc)Xd)0.5 XCorrect answer is option 'D'. Can you explain this answer?
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