3150 N......use first ...3rd equation of motion ....to..find acceleration ..n..then find force ....by ...m* a

Introduction:
In this scenario, we are given the weight and initial velocity of a bullet fired through a mud wall. We are also given the thickness of the mud wall and the final velocity of the bullet after passing through it. We need to find the average resistance offered by the mud wall.

Given:
- Weight of the bullet (m) = 10 grams = 0.01 kg
- Initial velocity of the bullet (u) = 800 m/s
- Final velocity of the bullet (v) = 100 m/s
- Thickness of the mud wall (d) = 1 meter

Calculating the average resistance:
The average resistance offered by the mud wall can be calculated using the formula:

R = m(v - u)/d

where R is the average resistance, m is the mass of the bullet, v is the final velocity, u is the initial velocity, and d is the thickness of the mud wall.

Substituting the given values into the formula:

R = (0.01 kg)(100 m/s - 800 m/s)/1 m

Simplifying the expression:

R = (0.01 kg)(-700 m/s)/1 m

R = -7 N

Explanation:
The negative sign in the average resistance (-7 N) indicates that the mud wall exerted a force opposite to the direction of motion of the bullet. This is due to the fact that the bullet experienced deceleration while passing through the mud wall, causing its velocity to decrease.

The average resistance offered by the mud wall is 7 N. This represents the average force exerted by the mud wall on the bullet over the distance of 1 meter. It is important to note that this is the average resistance, and the actual force exerted by the mud wall may vary during the deceleration process.

It is also worth mentioning that the resistance offered by the mud wall depends on various factors such as the velocity of the bullet, the density and composition of the mud, and the design and shape of the bullet.