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2gm of hydrogen are present in a closed vessel at S.T.P. If the same quantity of another gas X when introduced into the vessel the pressure becomes 1.5 atm. The gas X would be a) CH4 b)SO2 c) He d)O2. correct answer is option c. can you explain this answer?
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2gm of hydrogen are present in a closed vessel at S.T.P. If the same q...
Understanding the Given Problem
In this scenario, we have 2 g of hydrogen gas (H2) in a closed vessel at standard temperature and pressure (S.T.P). When another gas X is introduced, the total pressure rises to 1.5 atm.
Calculating Moles of Hydrogen
- The molar mass of hydrogen (H2) is approximately 2 g/mol.
- Therefore, moles of hydrogen = 2 g / 2 g/mol = 1 mol.
Using Ideal Gas Law
At S.T.P (1 atm, 273.15 K), 1 mole of any ideal gas occupies 22.4 L.
- The initial pressure due to hydrogen alone = 1 atm for 1 mol of H2.
When gas X is introduced, the total pressure becomes 1.5 atm. Thus,
Determining Contribution of Gas X
- The increase in pressure due to gas X = 1.5 atm - 1 atm = 0.5 atm.
Calculating Moles of Gas X
Using the ideal gas law (PV = nRT):
- Rearranging gives n = PV/RT.
- At S.T.P, R = 0.0821 L·atm/(K·mol) and T = 273.15 K.
For gas X, pressure = 0.5 atm, volume = 22.4 L:
- n = (0.5 atm * 22.4 L) / (0.0821 L·atm/(K·mol) * 273.15 K)
- This simplifies to approximately 0.5 mol of gas X.
Identifying Gas X
Now, we need to find a gas with a molar mass that fits with the moles calculated:
- CH4 (16 g/mol): 0.5 mol = 8 g → incorrect.
- SO2 (64 g/mol): 0.5 mol = 32 g → incorrect.
- O2 (32 g/mol): 0.5 mol = 16 g → incorrect.
- He (4 g/mol): 0.5 mol = 2 g → fits.
Thus, the correct identity of gas X is Helium (He).
In this scenario, we have 2 g of hydrogen gas (H2) in a closed vessel at standard temperature and pressure (S.T.P). When another gas X is introduced, the total pressure rises to 1.5 atm.
Calculating Moles of Hydrogen
- The molar mass of hydrogen (H2) is approximately 2 g/mol.
- Therefore, moles of hydrogen = 2 g / 2 g/mol = 1 mol.
Using Ideal Gas Law
At S.T.P (1 atm, 273.15 K), 1 mole of any ideal gas occupies 22.4 L.
- The initial pressure due to hydrogen alone = 1 atm for 1 mol of H2.
When gas X is introduced, the total pressure becomes 1.5 atm. Thus,
Determining Contribution of Gas X
- The increase in pressure due to gas X = 1.5 atm - 1 atm = 0.5 atm.
Calculating Moles of Gas X
Using the ideal gas law (PV = nRT):
- Rearranging gives n = PV/RT.
- At S.T.P, R = 0.0821 L·atm/(K·mol) and T = 273.15 K.
For gas X, pressure = 0.5 atm, volume = 22.4 L:
- n = (0.5 atm * 22.4 L) / (0.0821 L·atm/(K·mol) * 273.15 K)
- This simplifies to approximately 0.5 mol of gas X.
Identifying Gas X
Now, we need to find a gas with a molar mass that fits with the moles calculated:
- CH4 (16 g/mol): 0.5 mol = 8 g → incorrect.
- SO2 (64 g/mol): 0.5 mol = 32 g → incorrect.
- O2 (32 g/mol): 0.5 mol = 16 g → incorrect.
- He (4 g/mol): 0.5 mol = 2 g → fits.
Thus, the correct identity of gas X is Helium (He).
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2gm of hydrogen are present in a closed vessel at S.T.P. If the same quantity of another gas X when introduced into the vessel the pressure becomes 1.5 atm. The gas X would be a) CH4 b)SO2 c) He d)O2. correct answer is option c. can you explain this answer?
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2gm of hydrogen are present in a closed vessel at S.T.P. If the same quantity of another gas X when introduced into the vessel the pressure becomes 1.5 atm. The gas X would be a) CH4 b)SO2 c) He d)O2. correct answer is option c. can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 2gm of hydrogen are present in a closed vessel at S.T.P. If the same quantity of another gas X when introduced into the vessel the pressure becomes 1.5 atm. The gas X would be a) CH4 b)SO2 c) He d)O2. correct answer is option c. can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2gm of hydrogen are present in a closed vessel at S.T.P. If the same quantity of another gas X when introduced into the vessel the pressure becomes 1.5 atm. The gas X would be a) CH4 b)SO2 c) He d)O2. correct answer is option c. can you explain this answer?.
2gm of hydrogen are present in a closed vessel at S.T.P. If the same quantity of another gas X when introduced into the vessel the pressure becomes 1.5 atm. The gas X would be a) CH4 b)SO2 c) He d)O2. correct answer is option c. can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 2gm of hydrogen are present in a closed vessel at S.T.P. If the same quantity of another gas X when introduced into the vessel the pressure becomes 1.5 atm. The gas X would be a) CH4 b)SO2 c) He d)O2. correct answer is option c. can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2gm of hydrogen are present in a closed vessel at S.T.P. If the same quantity of another gas X when introduced into the vessel the pressure becomes 1.5 atm. The gas X would be a) CH4 b)SO2 c) He d)O2. correct answer is option c. can you explain this answer?.
Solutions for 2gm of hydrogen are present in a closed vessel at S.T.P. If the same quantity of another gas X when introduced into the vessel the pressure becomes 1.5 atm. The gas X would be a) CH4 b)SO2 c) He d)O2. correct answer is option c. can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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