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Two vessel of capacity 1.5 litres and 2 litres contain hydrogen gas and oxygen gas respectively under a pressure of 750mm and 100mm . The gases are mixed together Inna 5 litre vessel.what will be the final pressure of mixture?
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Two vessel of capacity 1.5 litres and 2 litres contain hydrogen gas an...
Answer:
Given:
- Capacity of the first vessel = 1.5 litres
- Capacity of the second vessel = 2 litres
- Pressure of hydrogen gas in the first vessel = 750mm
- Pressure of oxygen gas in the second vessel = 100mm
- Both gases are mixed in a 5 litre vessel
To find:
- Final pressure of the gas mixture
Solution:
Step 1: Calculation of moles of hydrogen and oxygen gas
- The number of moles of hydrogen gas in the first vessel can be calculated as follows:
- n = PV/RT
- P = 750mm Hg = 0.98 atm (approx)
- V = 1.5 litres
- R = 0.0821 L atm/K mol
- T = 273 + 25 = 298 K
- n = (0.98)(1.5)/(0.0821)(298) = 0.076 mol
- Similarly, the number of moles of oxygen gas in the second vessel can be calculated as follows:
- n = PV/RT
- P = 100mm Hg = 0.13 atm (approx)
- V = 2 litres
- R = 0.0821 L atm/K mol
- T = 273 + 25 = 298 K
- n = (0.13)(2)/(0.0821)(298) = 0.105 mol
Step 2: Calculation of total moles of gas mixture
- The total number of moles of gas mixture can be calculated as follows:
- n(total) = n(H2) + n(O2) = 0.076 + 0.105 = 0.181 mol
Step 3: Calculation of final pressure of gas mixture
- The final pressure of the gas mixture can be calculated using the following formula:
- P(total) = n(total)RT/V(total)
- R = 0.0821 L atm/K mol
- T = 273 + 25 = 298 K
- V(total) = 5 litres
- P(total) = (0.181)(0.0821)(298)/5 = 0.0087 atm (approx)
Step 4: Conversion of pressure to mm Hg
- The final pressure can be converted to mm Hg using the following formula:
- 1 atm = 760 mm Hg
- P(final) = 0.0087 atm x 760 mm Hg/atm = 6.6 mm Hg (approx)
Final Answer:
- The final pressure of the gas mixture is approximately 6.6 mm Hg.
Given:
- Capacity of the first vessel = 1.5 litres
- Capacity of the second vessel = 2 litres
- Pressure of hydrogen gas in the first vessel = 750mm
- Pressure of oxygen gas in the second vessel = 100mm
- Both gases are mixed in a 5 litre vessel
To find:
- Final pressure of the gas mixture
Solution:
Step 1: Calculation of moles of hydrogen and oxygen gas
- The number of moles of hydrogen gas in the first vessel can be calculated as follows:
- n = PV/RT
- P = 750mm Hg = 0.98 atm (approx)
- V = 1.5 litres
- R = 0.0821 L atm/K mol
- T = 273 + 25 = 298 K
- n = (0.98)(1.5)/(0.0821)(298) = 0.076 mol
- Similarly, the number of moles of oxygen gas in the second vessel can be calculated as follows:
- n = PV/RT
- P = 100mm Hg = 0.13 atm (approx)
- V = 2 litres
- R = 0.0821 L atm/K mol
- T = 273 + 25 = 298 K
- n = (0.13)(2)/(0.0821)(298) = 0.105 mol
Step 2: Calculation of total moles of gas mixture
- The total number of moles of gas mixture can be calculated as follows:
- n(total) = n(H2) + n(O2) = 0.076 + 0.105 = 0.181 mol
Step 3: Calculation of final pressure of gas mixture
- The final pressure of the gas mixture can be calculated using the following formula:
- P(total) = n(total)RT/V(total)
- R = 0.0821 L atm/K mol
- T = 273 + 25 = 298 K
- V(total) = 5 litres
- P(total) = (0.181)(0.0821)(298)/5 = 0.0087 atm (approx)
Step 4: Conversion of pressure to mm Hg
- The final pressure can be converted to mm Hg using the following formula:
- 1 atm = 760 mm Hg
- P(final) = 0.0087 atm x 760 mm Hg/atm = 6.6 mm Hg (approx)
Final Answer:
- The final pressure of the gas mixture is approximately 6.6 mm Hg.
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Two vessel of capacity 1.5 litres and 2 litres contain hydrogen gas and oxygen gas respectively under a pressure of 750mm and 100mm . The gases are mixed together Inna 5 litre vessel.what will be the final pressure of mixture?
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Two vessel of capacity 1.5 litres and 2 litres contain hydrogen gas and oxygen gas respectively under a pressure of 750mm and 100mm . The gases are mixed together Inna 5 litre vessel.what will be the final pressure of mixture? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two vessel of capacity 1.5 litres and 2 litres contain hydrogen gas and oxygen gas respectively under a pressure of 750mm and 100mm . The gases are mixed together Inna 5 litre vessel.what will be the final pressure of mixture? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two vessel of capacity 1.5 litres and 2 litres contain hydrogen gas and oxygen gas respectively under a pressure of 750mm and 100mm . The gases are mixed together Inna 5 litre vessel.what will be the final pressure of mixture?.
Two vessel of capacity 1.5 litres and 2 litres contain hydrogen gas and oxygen gas respectively under a pressure of 750mm and 100mm . The gases are mixed together Inna 5 litre vessel.what will be the final pressure of mixture? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two vessel of capacity 1.5 litres and 2 litres contain hydrogen gas and oxygen gas respectively under a pressure of 750mm and 100mm . The gases are mixed together Inna 5 litre vessel.what will be the final pressure of mixture? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two vessel of capacity 1.5 litres and 2 litres contain hydrogen gas and oxygen gas respectively under a pressure of 750mm and 100mm . The gases are mixed together Inna 5 litre vessel.what will be the final pressure of mixture?.
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