The heat combustion of CH4at constant volume in bonb calorimeter at 29...
The heat of combustion of a substance is the amount of heat produced when the substance is burned completely. The heat of combustion is usually measured under conditions of constant volume, which means that the volume of the system (in this case, the bomb calorimeter) is held constant during the reaction.
The enthalpy change for a reaction is the heat absorbed or released by the system during the reaction, at constant pressure. The enthalpy change is equal to the heat of combustion if the reaction is carried out at constant pressure.
In this case, the heat of combustion of CH4 at constant volume is given as -885389 J/mol. Since the reaction was carried out at constant volume, the enthalpy change for the reaction will also be -885389 J/mol.
Therefore, the value of the enthalpy change for the reaction is -885389 J/mol.
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The heat combustion of CH4at constant volume in bonb calorimeter at 29...
Enthalpy Change of the Combustion of CH4
The enthalpy change of a reaction can be determined by measuring the heat evolved or absorbed during the reaction. In this case, the heat combustion of CH4 (methane) is measured at constant volume using a bomb calorimeter at a temperature of 298.2 K. The measured heat is -885389 J/mol.
Definition of Enthalpy Change
Enthalpy change (ΔH) is the difference in enthalpy between the products and reactants of a reaction. It represents the heat energy exchanged during the reaction at constant pressure.
Relationship between Enthalpy Change and Heat
The heat evolved or absorbed during a reaction at constant volume (qV) is related to the enthalpy change (ΔH) by the equation:
qV = ΔH + ΔnRT
Where:
qV is the heat evolved or absorbed at constant volume,
ΔH is the enthalpy change of the reaction,
Δn is the change in the number of moles of gas,
R is the ideal gas constant, and
T is the temperature in Kelvin.
Calculating Enthalpy Change
In this case, the combustion of CH4 produces CO2 and H2O:
CH4 + 2O2 → CO2 + 2H2O
The number of moles of gas changes from 1 mole of CH4 to 3 moles of gas (1 mole of CO2 and 2 moles of H2O).
Using the equation qV = ΔH + ΔnRT, we can rearrange it to solve for ΔH:
ΔH = qV - ΔnRT
Substituting the given values, we have:
ΔH = -885389 J/mol - (3 mol)(8.314 J/mol·K)(298.2 K)
Calculating the value, we find:
ΔH ≈ -885389 J/mol - 74193 J/mol
ΔH ≈ -959582 J/mol
Therefore, the enthalpy change of the combustion of CH4 at constant volume is approximately -959582 J/mol.
Conclusion
The enthalpy change of the combustion of CH4 at constant volume is determined by measuring the heat evolved or absorbed during the reaction. Using the equation qV = ΔH + ΔnRT, the enthalpy change can be calculated by substituting the known values. In this case, the enthalpy change is found to be -959582 J/mol.
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