Statement I : B atom is sp2-hybridised in B2H6.Statement II : There is...
(d) B
2H
6 has following types of bonding
Bridging H-atoms and B-atoms are electron deficient. Each B-atom is however, joined to four H-atoms thus sp
3-hybridised.
There is no lone pair or unpaired electron.
Thus, Statement I is incorrect but Statement II is correct.
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Statement I : B atom is sp2-hybridised in B2H6.Statement II : There is...
Statement I: B atom is sp2-hybridized in B2H6.
Statement II: There is no lone pair or unpaired electron in B2H6.
Explanation:
Statement I: B atom is sp2-hybridized in B2H6.
In boron (B), the electronic configuration is 1s² 2s² 2p¹. When boron forms bonds, it undergoes hybridization to form sp2 hybrid orbitals. In the case of B2H6, boron forms three σ bonds with three hydrogen atoms. The three sp2 hybrid orbitals overlap with the 1s orbitals of the hydrogen atoms to form these σ bonds. This results in the formation of a trigonal planar structure around each boron atom.
Statement II: There is no lone pair or unpaired electron in B2H6.
In B2H6, boron forms three σ bonds with three hydrogen atoms, and each boron atom is also bonded to another boron atom through a bridge bond. This results in a total of six σ bonds in the molecule. Since boron only has three valence electrons, all of its valence electrons are involved in bonding, and there are no lone pairs or unpaired electrons on the boron atoms.
Explanation of the answer:
Statement I is correct because B atom in B2H6 is indeed sp2-hybridized. The formation of three σ bonds by each boron atom indicates sp2 hybridization.
Statement II is also correct because there are no lone pairs or unpaired electrons in B2H6. All valence electrons of boron are involved in bonding, resulting in a stable molecule without any unpaired or non-bonded electrons.
However, Statement II does not provide an explanation for Statement I. The absence of lone pairs or unpaired electrons does not directly explain the hybridization of boron in B2H6. Therefore, the correct answer is option D: Statement II is correct, but Statement I is incorrect.
Statement I : B atom is sp2-hybridised in B2H6.Statement II : There is...
B2H6 is sp3 hybridized. And it is electron deficient ......
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