Civil Engineering (CE) Exam > Civil Engineering (CE) Questions > The percentage of the fine aggregate of finen...
Start Learning for Free
The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :
- a)40%
- b)33%
- c)60%
- d)30%
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The percentage of the fine aggregate of fineness modulus 2.6 to be com...
Most Upvoted Answer
The percentage of the fine aggregate of fineness modulus 2.6 to be com...
Given:
Fineness modulus (FM) of fine aggregate = 2.6
Fineness modulus (FM) of coarse aggregate = 6.8
Fineness modulus (FM) of combined aggregates = 5.4
To find:
Percentage of fine aggregate required to be combined with coarse aggregate.
Solution:
1. Formula for fineness modulus:
Fineness modulus (FM) = Summation of cumulative percentage retained on standard sieves / 100
where the standard sieves are 4.75 mm, 2.36 mm, 1.18 mm, 600 microns, 300 microns, 150 microns and 75 microns.
2. Calculation of cumulative percentage retained on standard sieves:
For fine aggregate:
Given FM = 2.6
We can assume that the percentage of material retained on the 600 micron sieve is 100 for FM 2.0 to 3.0.
Therefore, cumulative percentage retained on standard sieves for FM 2.6 can be calculated as follows:
Cumulative percentage retained on 4.75 mm sieve = 0
Cumulative percentage retained on 2.36 mm sieve = 0
Cumulative percentage retained on 1.18 mm sieve = 0
Cumulative percentage retained on 600 micron sieve = 100
Cumulative percentage retained on 300 micron sieve = 88
Cumulative percentage retained on 150 micron sieve = 56
Cumulative percentage retained on 75 micron sieve = 34
For coarse aggregate:
Given FM = 6.8
We can assume that the percentage of material retained on the 4.75 mm sieve is 100 for FM 6.5 to 7.0.
Therefore, cumulative percentage retained on standard sieves for FM 6.8 can be calculated as follows:
Cumulative percentage retained on 4.75 mm sieve = 100
Cumulative percentage retained on 2.36 mm sieve = 97
Cumulative percentage retained on 1.18 mm sieve = 89
Cumulative percentage retained on 600 micron sieve = 61
Cumulative percentage retained on 300 micron sieve = 26
Cumulative percentage retained on 150 micron sieve = 6
Cumulative percentage retained on 75 micron sieve = 1
3. Calculation of combined aggregates:
Given FM of combined aggregates = 5.4
We need to assume a percentage of fine aggregate to be combined with coarse aggregate to obtain FM 5.4.
Let us assume that the percentage of fine aggregate is x.
Therefore, the percentage of coarse aggregate is (100 - x).
Using the formula for fineness modulus, we can calculate the cumulative percentage retained on standard sieves for combined aggregates as follows:
Cumulative percentage retained on 4.75 mm sieve = 100 - x
Cumulative percentage retained on 2.36 mm sieve = 97 - 2.6x/3.2
Cumulative percentage retained on 1.18 mm sieve = 89 - 2.6x/1.8
Cumulative percentage retained on 600 micron sieve = 61 - 2.6x/3.4
Cumulative percentage retained on 300 micron sieve = 26 + 2.6x/12.6
Cumulative percentage retained on 150 micron sieve = 6 + 2.6x/9
Cumulative percentage
Fineness modulus (FM) of fine aggregate = 2.6
Fineness modulus (FM) of coarse aggregate = 6.8
Fineness modulus (FM) of combined aggregates = 5.4
To find:
Percentage of fine aggregate required to be combined with coarse aggregate.
Solution:
1. Formula for fineness modulus:
Fineness modulus (FM) = Summation of cumulative percentage retained on standard sieves / 100
where the standard sieves are 4.75 mm, 2.36 mm, 1.18 mm, 600 microns, 300 microns, 150 microns and 75 microns.
2. Calculation of cumulative percentage retained on standard sieves:
For fine aggregate:
Given FM = 2.6
We can assume that the percentage of material retained on the 600 micron sieve is 100 for FM 2.0 to 3.0.
Therefore, cumulative percentage retained on standard sieves for FM 2.6 can be calculated as follows:
Cumulative percentage retained on 4.75 mm sieve = 0
Cumulative percentage retained on 2.36 mm sieve = 0
Cumulative percentage retained on 1.18 mm sieve = 0
Cumulative percentage retained on 600 micron sieve = 100
Cumulative percentage retained on 300 micron sieve = 88
Cumulative percentage retained on 150 micron sieve = 56
Cumulative percentage retained on 75 micron sieve = 34
For coarse aggregate:
Given FM = 6.8
We can assume that the percentage of material retained on the 4.75 mm sieve is 100 for FM 6.5 to 7.0.
Therefore, cumulative percentage retained on standard sieves for FM 6.8 can be calculated as follows:
Cumulative percentage retained on 4.75 mm sieve = 100
Cumulative percentage retained on 2.36 mm sieve = 97
Cumulative percentage retained on 1.18 mm sieve = 89
Cumulative percentage retained on 600 micron sieve = 61
Cumulative percentage retained on 300 micron sieve = 26
Cumulative percentage retained on 150 micron sieve = 6
Cumulative percentage retained on 75 micron sieve = 1
3. Calculation of combined aggregates:
Given FM of combined aggregates = 5.4
We need to assume a percentage of fine aggregate to be combined with coarse aggregate to obtain FM 5.4.
Let us assume that the percentage of fine aggregate is x.
Therefore, the percentage of coarse aggregate is (100 - x).
Using the formula for fineness modulus, we can calculate the cumulative percentage retained on standard sieves for combined aggregates as follows:
Cumulative percentage retained on 4.75 mm sieve = 100 - x
Cumulative percentage retained on 2.36 mm sieve = 97 - 2.6x/3.2
Cumulative percentage retained on 1.18 mm sieve = 89 - 2.6x/1.8
Cumulative percentage retained on 600 micron sieve = 61 - 2.6x/3.4
Cumulative percentage retained on 300 micron sieve = 26 + 2.6x/12.6
Cumulative percentage retained on 150 micron sieve = 6 + 2.6x/9
Cumulative percentage
Free Test
FREE
| Start Free Test |
Community Answer
The percentage of the fine aggregate of fineness modulus 2.6 to be com...
fineness modulus of combine mix(z) = 5.4
fineness modulus of coarse aggregate (x) = 6.8
fineness modulus of fine aggregate (y) = 2.8
Percentage of fine aggregate
p = (x-z)/(z-y)×100=(6.8-5.4)/(5.4-2.8)×100
= 53% ⋍ 50%
fineness modulus of coarse aggregate (x) = 6.8
fineness modulus of fine aggregate (y) = 2.8
Percentage of fine aggregate
p = (x-z)/(z-y)×100=(6.8-5.4)/(5.4-2.8)×100
= 53% ⋍ 50%
Attention Civil Engineering (CE) Students!
To make sure you are not studying endlessly, EduRev has designed Civil Engineering (CE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Civil Engineering (CE).
|
Explore Courses for Civil Engineering (CE) exam
|
|
Similar Civil Engineering (CE) Doubts
Top Courses for Civil Engineering (CE)View all
The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer?
Question Description
The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer?.
The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer?.
Solutions for The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Here you can find the meaning of The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The percentage of the fine aggregate of fineness modulus 2.6 to be combined with coarseaggregate of fineness modulus 6.8 for obtaining the aggregates of fineness modulus 5.4, is :a)40%b)33%c)60%d)30%Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
|
|
Explore Courses for Civil Engineering (CE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup