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A boy thrown an object horizontally with the velocity of 6m/s through the window of the bus moving with a velocity of 36km/hr. If the height of the window from the ground is 3m and the object is thrown normal to the motion of the bus what is the velocity of impact on the ground?
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A boy thrown an object horizontally with the velocity of 6m/s through ...
Analysis
To solve this problem, we need to consider the horizontal and vertical components of motion separately. The horizontal component of motion is unaffected by the motion of the bus, while the vertical component of motion is affected by both the initial velocity of the object and the vertical motion of the bus.
Horizontal Motion
The boy throws the object horizontally with a velocity of 6 m/s. Since there is no acceleration in the horizontal direction, the horizontal velocity of the object remains constant throughout its motion.
Vertical Motion
The bus is moving with a velocity of 36 km/hr. To make the units consistent, we need to convert this velocity to m/s.
Speed of the bus = 36 km/hr = 36 * (1000/3600) m/s = 10 m/s
The object is thrown normal to the motion of the bus, which means that its vertical velocity is not affected by the motion of the bus. Therefore, the initial vertical velocity of the object is 0 m/s.
The height of the window from the ground is given as 3 m, which means that the object will fall vertically downwards from this height.
Vertical Motion Calculation
We can use the equation of motion for vertical motion to calculate the time taken by the object to reach the ground.
We know that the initial vertical velocity (u) is 0 m/s, the acceleration due to gravity (g) is approximately 9.8 m/s^2, and the displacement (h) is 3 m.
Using the equation h = ut + (1/2)gt^2, we can substitute the known values to find the time (t).
3 = 0 * t + (1/2) * 9.8 * t^2
3 = 4.9 * t^2
t^2 = 3/4.9
t ≈ 0.782 s
Velocity of Impact on the Ground
Now that we know the time taken by the object to reach the ground, we can calculate the horizontal distance traveled by the object during this time.
The horizontal distance (d) traveled by the object is given by the equation d = v * t, where v is the horizontal velocity of the object and t is the time taken.
Since the horizontal velocity of the object is 6 m/s and the time taken is approximately 0.782 s, we can substitute these values to find the horizontal distance.
d = 6 * 0.782
d ≈ 4.692 m
Therefore, the velocity of impact on the ground is equal to the horizontal velocity of the object, which is 6 m/s.
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A boy thrown an object horizontally with the velocity of 6m/s through ...
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A boy thrown an object horizontally with the velocity of 6m/s through the window of the bus moving with a velocity of 36km/hr. If the height of the window from the ground is 3m and the object is thrown normal to the motion of the bus what is the velocity of impact on the ground?
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