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An object is thrown up from a planet whose mass is twice that of the earth and radius of the radius of the earth to a height of 50 M find the velocity with which it was thrown at the time taken to reach the maximum height?
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An object is thrown up from a planet whose mass is twice that of the e...
Introduction
To calculate the velocity with which the object was thrown from a planet with twice the mass and radius of Earth, we first need to understand the gravitational acceleration on this planet.
Gravitational Acceleration
- The gravitational acceleration (g) on a planet is given by the formula:
g = G * (M/R^2)
- For Earth:
- Mass (M) = Mass of Earth
- Radius (R) = Radius of Earth
- For the given planet:
- Mass = 2 * Mass of Earth
- Radius = 2 * Radius of Earth
- Thus, the gravitational acceleration on the new planet:
g' = G * (2M / (2R)^2) = G * (2M / 4R^2) = (1/2) * g
This means the gravitational acceleration on this planet is half that of Earth's.
Height and Maximum Velocity
- The maximum height (h) reached by the object is given as 50 m.
- At maximum height, the final velocity (v) becomes zero. Using the kinematic equation:
v^2 = u^2 + 2gh, we can re-arrange it to find initial velocity (u):
- Setting v = 0:
0 = u^2 - 2 * (1/2)g * 50
- Simplifying:
u^2 = g * 50
u = √(g * 50)
Time to Reach Maximum Height
- The time (t) to reach maximum height can be calculated using:
v = u - gt
- Rearranging gives:
t = u/g
Conclusion
- Calculate the values based on the gravitational acceleration of the planet and plug them into the equations to find the velocity and time taken to reach the maximum height.
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An object is thrown up from a planet whose mass is twice that of the earth and radius of the radius of the earth to a height of 50 M find the velocity with which it was thrown at the time taken to reach the maximum height?
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