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A ball is thrown with a velocity of 20m/s. Find
a]the maximum height to which it rises
b]the time it would take to reach maximum height
c]the time it would take to return back to thrower?
?
a]the maximum height to which it rises
b]the time it would take to reach maximum height
c]the time it would take to return back to thrower?
?
Most Upvoted Answer
A ball is thrown with a velocity of 20m/s. Find a]the maximum height t...
Hi!
When a body is projected vertically upwards,
Assuming that g= 10m/s^2
a] max. height = (u^2)/2g
= 400/20
= 20 m
b] time of ascent = u/g
= 20/10
= 2 sec
c] time of descent = time of ascent = u/g = 2 sec
Therefore, in one statement, A ball thrown with a velocity of 20 m/s reaches a maximum height of 20 meters in 2 seconds and returns back to the thrower 2 seconds later.
This question can be solved using the equations of motion as well.
b,c] v=u+at
0= 20 + 10t
20/10= t
2 = t
time of ascent and descent are equal.
a] s= ut-1/2at^2
= 40-20
=20 m
Community Answer
A ball is thrown with a velocity of 20m/s. Find a]the maximum height t...
Projectile Motion Problem
Given:
- Initial velocity of the ball, u = 20m/s
- Acceleration due to gravity, g = 9.8m/s^2
Calculations:
Maximum Height:
The maximum height is obtained when the vertical component of the velocity is zero. Using the equation:
v^2 = u^2 + 2gh
where v = final velocity, u = initial velocity, g = acceleration due to gravity, and h = maximum height
At maximum height, v = 0
Therefore, 0 = 20^2 - 2(9.8)h
h = 20.4m
Time to reach Maximum Height:
The time taken to reach maximum height can be calculated using the equation:
h = ut + 0.5gt^2
where t = time taken
At maximum height, the final vertical velocity is zero.
Therefore, 0 = 20 - 9.8t
t = 2.04s
Time to return to the Thrower:
The total time of flight can be calculated using the equation:
t = 2u/g
where t = time of flight
Substituting the given values, we get:
t = 2(20)/9.8
t = 4.08s
Answer:
- The maximum height to which the ball rises is 20.4m.
- The time it takes to reach the maximum height is 2.04s.
- The time it takes to return back to the thrower is 4.08s.
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A ball is thrown with a velocity of 20m/s. Find a]the maximum height to which it risesb]the time it would take to reach maximum heightc]the time it would take to return back to thrower??
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A ball is thrown with a velocity of 20m/s. Find a]the maximum height to which it risesb]the time it would take to reach maximum heightc]the time it would take to return back to thrower?? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A ball is thrown with a velocity of 20m/s. Find a]the maximum height to which it risesb]the time it would take to reach maximum heightc]the time it would take to return back to thrower?? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is thrown with a velocity of 20m/s. Find a]the maximum height to which it risesb]the time it would take to reach maximum heightc]the time it would take to return back to thrower??.
A ball is thrown with a velocity of 20m/s. Find a]the maximum height to which it risesb]the time it would take to reach maximum heightc]the time it would take to return back to thrower?? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A ball is thrown with a velocity of 20m/s. Find a]the maximum height to which it risesb]the time it would take to reach maximum heightc]the time it would take to return back to thrower?? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is thrown with a velocity of 20m/s. Find a]the maximum height to which it risesb]the time it would take to reach maximum heightc]the time it would take to return back to thrower??.
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