Find the velocity with which a ball is thrown up if it reaches the maximum height in 5sec. Also find the maximum height.?

Question

Answer

U=0 t=5s a=10m/s^2... Minimum height=s=ut+1/2at^2... =(1/2)×10×25m=125m... Velocity=v... v^2=u^2+2as.. v^2=2×10×125.. v=Root2500 m/s=50m/s....

Answer

Answer

Understanding the Problem:
To find the velocity with which a ball is thrown up and the maximum height it reaches in 5 seconds, we need to utilize the equations of motion for projectile motion.

Finding the Initial Velocity:
- Let's assume the initial velocity of the ball when thrown up is 'u' m/s.
- At the maximum height, the vertical component of the velocity becomes 0 m/s.
- Using the equation v = u + at, where v = final velocity, u = initial velocity, a = acceleration (in this case, acceleration due to gravity), and t = time.
- Here, final velocity v = 0 m/s, acceleration a = -9.81 m/s² (as the ball is moving against gravity), and time t = 5 seconds.
- Substituting the values, we get 0 = u - 9.81 * 5
- Solving the equation, we find the initial velocity 'u' of the ball.

Finding the Maximum Height:
- The maximum height 'h' can be determined using the equation h = ut + (1/2)at², where h = height, u = initial velocity, t = time, and a = acceleration.
- Substituting the values, we get h = ut + (1/2)at²
- Substituting the values of 'u' and 't', we can calculate the maximum height the ball reaches.

Conclusion:
By following these steps, we can determine the initial velocity of the ball when thrown up and the maximum height it reaches in 5 seconds. This process helps in understanding the principles of projectile motion and applying the equations of motion to solve such problems effectively.

Similar Class 9 Doubts

if a ball is thrown up with a velocity V,it reaches a maximum height h.if one wishes to triple the maximum height then ball should be thrown with what velocity

A ball thrown up vertically returns to the thrower after 6s, find (i). the velocity with which it was thrown up, (ii). the maximum height it reach and (iii). its position after 4s?

A piece of stone is thrown vertically upwards it reaches its Max Height in 3 seconds if the acceleration of the stone is 9.8 minutes / S² directed upwards calculate the initial velocity with which it is thrown upward find the Max Height attained by it?

A ball is thrown with a velocity of 20m/s. Find a]the maximum height to which it risesb]the time it would take to reach maximum heightc]the time it would take to return back to thrower??

A ball is thrown vertically upward a velocity of 14 m/s. Calculate 1. The maximum height attained 2.The time taken by it before it reaches the ground again?

Top Courses for Class 9View all

Science Class 9

Social Studies (SST) Class 9

Mathematics (Maths) Class 9

English Class 9

English Grammar Advanced

Top Courses for Class 9

Top Courses for Class 9

Suggested Free Tests

Related Content

Class 9 Study Material

Class 9 Subjects

Competitive Examinations for Class 9

NCERT Books

NCERT Solutions

Reference Books for Class 9

Other Popular Exams

Company