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Which of the following statements is/are true?
(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms
(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.
(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.
- a)I & III
- b)II & III
- c)All
- d)I & II.
Correct answer is option 'A'. Can you explain this answer?
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Which of the following statements is/are true?(I) If H atoms are in 3r...
Here, the electrons of each hydrogen atom are in same state hence in transition will emit photons of equal wavelengths for each transition hence, the maximum spectral lines emitted are 6.
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Which of the following statements is/are true?(I) If H atoms are in 3r...
I Explanation:
To analyze the given statements, let's consider the energy levels and transitions in hydrogen and helium atoms.
I. If H atoms are in the 3rd state, then the number of maximum spectral lines produced by 2 atoms will be equal to the number of maximum spectral lines produced by 3 H-atoms.
- In the hydrogen atom, the energy levels are given by the formula Eₙ = -13.6/n², where n is the principal quantum number.
- The number of spectral lines emitted during the transition from one energy level to another is given by the formula N = n(n-1)/2.
- For a hydrogen atom in the 3rd excited state (n = 4), the number of spectral lines produced is N = 4(4-1)/2 = 6.
- Therefore, for 2 hydrogen atoms in the 3rd excited state, the total number of spectral lines produced will be 2 * 6 = 12.
- On the other hand, for 3 hydrogen atoms in the ground state, the total number of spectral lines produced will be 3 * 0 = 0.
- Hence, the statement is false. Therefore, statement I is not true.
II. For the third excited state, the maximum number of spectral lines produced by helium and the maximum number of spectral lines produced by 4 H-atoms are not equal.
- For helium, the energy levels are given by the formula Eₙ = -54.4/n², where n is the principal quantum number.
- For the third excited state of helium (n = 4), the number of spectral lines produced is N = 4(4-1)/2 = 6.
- For 4 hydrogen atoms in the ground state, the total number of spectral lines produced is N = 4 * 0 = 0.
- Hence, the statement is true. Therefore, statement II is true.
III. Energy evolved from 3 to 2 transitions in He cannot be used for any transition in Li2.
- The energy levels of helium and lithium atoms are different.
- The energy difference between the 3rd and 2nd energy levels in helium cannot be used for any transitions in lithium.
- Hence, the statement is true. Therefore, statement III is true.
Therefore, the correct statements are II and III. Option A, which includes statements I and III, is the correct answer.
To analyze the given statements, let's consider the energy levels and transitions in hydrogen and helium atoms.
I. If H atoms are in the 3rd state, then the number of maximum spectral lines produced by 2 atoms will be equal to the number of maximum spectral lines produced by 3 H-atoms.
- In the hydrogen atom, the energy levels are given by the formula Eₙ = -13.6/n², where n is the principal quantum number.
- The number of spectral lines emitted during the transition from one energy level to another is given by the formula N = n(n-1)/2.
- For a hydrogen atom in the 3rd excited state (n = 4), the number of spectral lines produced is N = 4(4-1)/2 = 6.
- Therefore, for 2 hydrogen atoms in the 3rd excited state, the total number of spectral lines produced will be 2 * 6 = 12.
- On the other hand, for 3 hydrogen atoms in the ground state, the total number of spectral lines produced will be 3 * 0 = 0.
- Hence, the statement is false. Therefore, statement I is not true.
II. For the third excited state, the maximum number of spectral lines produced by helium and the maximum number of spectral lines produced by 4 H-atoms are not equal.
- For helium, the energy levels are given by the formula Eₙ = -54.4/n², where n is the principal quantum number.
- For the third excited state of helium (n = 4), the number of spectral lines produced is N = 4(4-1)/2 = 6.
- For 4 hydrogen atoms in the ground state, the total number of spectral lines produced is N = 4 * 0 = 0.
- Hence, the statement is true. Therefore, statement II is true.
III. Energy evolved from 3 to 2 transitions in He cannot be used for any transition in Li2.
- The energy levels of helium and lithium atoms are different.
- The energy difference between the 3rd and 2nd energy levels in helium cannot be used for any transitions in lithium.
- Hence, the statement is true. Therefore, statement III is true.
Therefore, the correct statements are II and III. Option A, which includes statements I and III, is the correct answer.
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Which of the following statements is/are true?(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.a)I & IIIb)II & IIIc)Alld)I & II.Correct answer is option 'A'. Can you explain this answer?
Question Description
Which of the following statements is/are true?(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.a)I & IIIb)II & IIIc)Alld)I & II.Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following statements is/are true?(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.a)I & IIIb)II & IIIc)Alld)I & II.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following statements is/are true?(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.a)I & IIIb)II & IIIc)Alld)I & II.Correct answer is option 'A'. Can you explain this answer?.
Which of the following statements is/are true?(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.a)I & IIIb)II & IIIc)Alld)I & II.Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following statements is/are true?(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.a)I & IIIb)II & IIIc)Alld)I & II.Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following statements is/are true?(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.a)I & IIIb)II & IIIc)Alld)I & II.Correct answer is option 'A'. Can you explain this answer?.
Solutions for Which of the following statements is/are true?(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.a)I & IIIb)II & IIIc)Alld)I & II.Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Which of the following statements is/are true?(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.a)I & IIIb)II & IIIc)Alld)I & II.Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Which of the following statements is/are true?(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.a)I & IIIb)II & IIIc)Alld)I & II.Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Which of the following statements is/are true?(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.a)I & IIIb)II & IIIc)Alld)I & II.Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Which of the following statements is/are true?(I) If H atoms are in 3rd state then number of maximum spectral line produced by 2 atoms will be equal to number of maximum spectral lines produced by 3 H-atoms(II) For third excited state, maximum number of spectral line produced by He+ and maximum number of spectral line produced by 4 H - atom are not equal.(III) Energy evolved from 3 to 2 transitions in He cannot used for any transition in Li2+.a)I & IIIb)II & IIIc)Alld)I & II.Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
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