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If an electron is in any higher state n = n and makes a transition to ground state, then total no. of different photons emitted is equal to 
If an electrons is in any higher state n = n2 and makes a transition to another excited state n = n1, then total no. of different photons emitted is equal to
where Δ n = n 2 – n 1 .
Note: In case of single isolated atom if electron make transition from nth state to the ground state then max. number of spectral lines observed = ( n – 1).
Q.
Two samples are taken, in 1st sample mole ratio of H to H+ is 1: 2. In IInd sample mole ratio of H to He+ is 2: 1. If n1 is number of spectral lines produced by 1st sample and number of spectral lines produced by lino sample is n2 then n1: n2 will be – (There is sufficient number of both types of atom and both are in same excited state in both sample)
  • a)
    2 : 1
  • b)
    1 : 2
  • c)
    1 : 1
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If an electron is in any higher state n = n and makes a transition to ...
The number of spectral lines will be same no matter how many atoms more than required number of atoms are provided.in 1st sample sum of spectral lines in H and He+ is n1.so n2 will also be equal to n1 as explained earlier.so n1:n2=1:1
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The only electron in the hydrogen atom resides under ordinary conditions on the first orbit. When energy is supplied, the electron moves to higher energy orbit depending on the amount of energy absorbed. When this electron returns to any of the lower orbits, it emits energy. Lyman series is formed when the electron returns to the lowest orbit while Balmer series is formed when the electron returns to second orbit. Similarly, Paschen, Brackett and Pfund series are formed when electron returns to the third, fourth and fifth orbits from higher energy orbits respectively. Maximum number of lines produced when an electron jumps from nth level to ground level is equal to . For examle, in the case of n = 4, number of lines produced is 6. (4 3, 4 2, 4 1, 3 2, 3 1, 2 1). When an electron returns from n2 to n1 state, the number of lines in the spectrum will be equal toIf the electron comes back from energy level having energy E2 to energy level having energy E1, then the difference may be expressed in terms of energy of photon as :Since h and c are constants, E corresponds to definite energy; thus each transition from one energy level to another will produce a light of definite wavelength. This is actually observed as a line in the spectrum of hydrogen atom.Wave number of line is given by the formulawhere R is a Rydbergs constant(R = 1.1 107 m-1)Q.In a collection of Hatom, electrons make transition from 5th excited state to 2nd excited state then maximum number of different types of photons observed are

If an electron is in any higher state n = n and makes a transition to ground state, then total no. of different photons emitted is equal to If an electrons is in any higher state n = n2 and makes a transition to another excited state n = n1, then total no. of different photons emitted is equal to where Δ n = n 2 – n 1 .Note: In case of single isolated atom if electron make transition from nth state to the ground state then max. number of spectral lines observed = ( n – 1).Q.Two samples are taken, in 1st sample mole ratio of H to H+ is 1: 2. In IInd sample mole ratio of H to He+ is 2: 1. If n1 is number of spectral lines produced by 1st sample and number of spectral lines produced by lino sample is n2 then n1: n2 will be – (There is sufficient number of both types of atom and both are in same excited state in both sample)a)2 : 1b)1 : 2c)1 : 1d)None of theseCorrect answer is option 'C'. Can you explain this answer?
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If an electron is in any higher state n = n and makes a transition to ground state, then total no. of different photons emitted is equal to If an electrons is in any higher state n = n2 and makes a transition to another excited state n = n1, then total no. of different photons emitted is equal to where Δ n = n 2 – n 1 .Note: In case of single isolated atom if electron make transition from nth state to the ground state then max. number of spectral lines observed = ( n – 1).Q.Two samples are taken, in 1st sample mole ratio of H to H+ is 1: 2. In IInd sample mole ratio of H to He+ is 2: 1. If n1 is number of spectral lines produced by 1st sample and number of spectral lines produced by lino sample is n2 then n1: n2 will be – (There is sufficient number of both types of atom and both are in same excited state in both sample)a)2 : 1b)1 : 2c)1 : 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If an electron is in any higher state n = n and makes a transition to ground state, then total no. of different photons emitted is equal to If an electrons is in any higher state n = n2 and makes a transition to another excited state n = n1, then total no. of different photons emitted is equal to where Δ n = n 2 – n 1 .Note: In case of single isolated atom if electron make transition from nth state to the ground state then max. number of spectral lines observed = ( n – 1).Q.Two samples are taken, in 1st sample mole ratio of H to H+ is 1: 2. In IInd sample mole ratio of H to He+ is 2: 1. If n1 is number of spectral lines produced by 1st sample and number of spectral lines produced by lino sample is n2 then n1: n2 will be – (There is sufficient number of both types of atom and both are in same excited state in both sample)a)2 : 1b)1 : 2c)1 : 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If an electron is in any higher state n = n and makes a transition to ground state, then total no. of different photons emitted is equal to If an electrons is in any higher state n = n2 and makes a transition to another excited state n = n1, then total no. of different photons emitted is equal to where Δ n = n 2 – n 1 .Note: In case of single isolated atom if electron make transition from nth state to the ground state then max. number of spectral lines observed = ( n – 1).Q.Two samples are taken, in 1st sample mole ratio of H to H+ is 1: 2. In IInd sample mole ratio of H to He+ is 2: 1. If n1 is number of spectral lines produced by 1st sample and number of spectral lines produced by lino sample is n2 then n1: n2 will be – (There is sufficient number of both types of atom and both are in same excited state in both sample)a)2 : 1b)1 : 2c)1 : 1d)None of theseCorrect answer is option 'C'. Can you explain this answer?.
Solutions for If an electron is in any higher state n = n and makes a transition to ground state, then total no. of different photons emitted is equal to If an electrons is in any higher state n = n2 and makes a transition to another excited state n = n1, then total no. of different photons emitted is equal to where Δ n = n 2 – n 1 .Note: In case of single isolated atom if electron make transition from nth state to the ground state then max. number of spectral lines observed = ( n – 1).Q.Two samples are taken, in 1st sample mole ratio of H to H+ is 1: 2. In IInd sample mole ratio of H to He+ is 2: 1. If n1 is number of spectral lines produced by 1st sample and number of spectral lines produced by lino sample is n2 then n1: n2 will be – (There is sufficient number of both types of atom and both are in same excited state in both sample)a)2 : 1b)1 : 2c)1 : 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of If an electron is in any higher state n = n and makes a transition to ground state, then total no. of different photons emitted is equal to If an electrons is in any higher state n = n2 and makes a transition to another excited state n = n1, then total no. of different photons emitted is equal to where Δ n = n 2 – n 1 .Note: In case of single isolated atom if electron make transition from nth state to the ground state then max. number of spectral lines observed = ( n – 1).Q.Two samples are taken, in 1st sample mole ratio of H to H+ is 1: 2. In IInd sample mole ratio of H to He+ is 2: 1. If n1 is number of spectral lines produced by 1st sample and number of spectral lines produced by lino sample is n2 then n1: n2 will be – (There is sufficient number of both types of atom and both are in same excited state in both sample)a)2 : 1b)1 : 2c)1 : 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of If an electron is in any higher state n = n and makes a transition to ground state, then total no. of different photons emitted is equal to If an electrons is in any higher state n = n2 and makes a transition to another excited state n = n1, then total no. of different photons emitted is equal to where Δ n = n 2 – n 1 .Note: In case of single isolated atom if electron make transition from nth state to the ground state then max. number of spectral lines observed = ( n – 1).Q.Two samples are taken, in 1st sample mole ratio of H to H+ is 1: 2. In IInd sample mole ratio of H to He+ is 2: 1. If n1 is number of spectral lines produced by 1st sample and number of spectral lines produced by lino sample is n2 then n1: n2 will be – (There is sufficient number of both types of atom and both are in same excited state in both sample)a)2 : 1b)1 : 2c)1 : 1d)None of theseCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for If an electron is in any higher state n = n and makes a transition to ground state, then total no. of different photons emitted is equal to If an electrons is in any higher state n = n2 and makes a transition to another excited state n = n1, then total no. of different photons emitted is equal to where Δ n = n 2 – n 1 .Note: In case of single isolated atom if electron make transition from nth state to the ground state then max. number of spectral lines observed = ( n – 1).Q.Two samples are taken, in 1st sample mole ratio of H to H+ is 1: 2. In IInd sample mole ratio of H to He+ is 2: 1. If n1 is number of spectral lines produced by 1st sample and number of spectral lines produced by lino sample is n2 then n1: n2 will be – (There is sufficient number of both types of atom and both are in same excited state in both sample)a)2 : 1b)1 : 2c)1 : 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of If an electron is in any higher state n = n and makes a transition to ground state, then total no. of different photons emitted is equal to If an electrons is in any higher state n = n2 and makes a transition to another excited state n = n1, then total no. of different photons emitted is equal to where Δ n = n 2 – n 1 .Note: In case of single isolated atom if electron make transition from nth state to the ground state then max. number of spectral lines observed = ( n – 1).Q.Two samples are taken, in 1st sample mole ratio of H to H+ is 1: 2. In IInd sample mole ratio of H to He+ is 2: 1. If n1 is number of spectral lines produced by 1st sample and number of spectral lines produced by lino sample is n2 then n1: n2 will be – (There is sufficient number of both types of atom and both are in same excited state in both sample)a)2 : 1b)1 : 2c)1 : 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice If an electron is in any higher state n = n and makes a transition to ground state, then total no. of different photons emitted is equal to If an electrons is in any higher state n = n2 and makes a transition to another excited state n = n1, then total no. of different photons emitted is equal to where Δ n = n 2 – n 1 .Note: In case of single isolated atom if electron make transition from nth state to the ground state then max. number of spectral lines observed = ( n – 1).Q.Two samples are taken, in 1st sample mole ratio of H to H+ is 1: 2. In IInd sample mole ratio of H to He+ is 2: 1. If n1 is number of spectral lines produced by 1st sample and number of spectral lines produced by lino sample is n2 then n1: n2 will be – (There is sufficient number of both types of atom and both are in same excited state in both sample)a)2 : 1b)1 : 2c)1 : 1d)None of theseCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
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