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Pth term of an ap is a and qth term is b prove that the sum of its (p q)th?
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Pth term of an ap is a and qth term is b prove that the sum of its (p ...
Let the first term of the AP be 'c' and its common difference be 'd'.  

 So its pth term is: c + (p - 1)d = a ------ (1)  
and its qth term is: c + (q - 1)d = b ----- (2)  

Adding (1) & (2): 2c + (p + q - 2)d = a + b  

==> 2c + (p + q - 1)d - d = a + b  

==> 2c + (p + q - 1)d = (a + b) + d ---------- (3)  
Operating (1) - (2): (p - q)d = (a - b)  
==> d = (a - b)/(p - q) --------- (4)  

Sum to (p + q) terms is:  
S₍p+q₎ = {(p + q)/2}*{2c + (p + q - 1)d} 

Substituting from (3) and (4), we get 


S₍p+q₎ = {(p + q)/2}*{(a + b) + (a - b)/(p - q)} --

hence proved
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Pth term of an ap is a and qth term is b prove that the sum of its (p ...
Proof:

Let's consider an arithmetic progression (AP) with the first term a and the common difference d.

The pth term of this AP can be expressed as:
a + (p-1)d

Similarly, the qth term can be expressed as:
a + (q-1)d

To prove that the sum of the (p+q)th term is equal to (p+q) times the average of the pth and qth term, we need to find the (p+q)th term and the average of the pth and qth term.

Finding the (p+q)th term:
The (p+q)th term can be expressed as:
a + (p+q-1)d

Finding the average of the pth and qth term:
The average of the pth and qth term can be calculated as:
(a + (p-1)d + a + (q-1)d) / 2
Simplifying this expression gives:
(2a + (p+q-2)d) / 2

Proving the equality:
To prove that the sum of the (p+q)th term is equal to (p+q) times the average of the pth and qth term, we need to show that:
(a + (p+q-1)d) = (p+q) * [(2a + (p+q-2)d) / 2]

Multiplying both sides by 2 gives:
2a + 2(p+q-1)d = (p+q) * (2a + (p+q-2)d)

Expanding the right side gives:
2a + 2(p+q-1)d = 2a(p+q) + (p+q)(p+q-2)d

Simplifying both sides gives:
2a + 2pd + 2qd - 2d = 2ap + 2aq + p^2d + pqd + pqd + q^2d - 2pd - 2qd

Cancelling out the terms on both sides gives:
2a - 2d = 2ap + 2aq + p^2d + 2pqd + q^2d - 2pd - 2qd

Further simplifying gives:
2a - 2d = 2ap + 2aq + p^2d + 2pqd + q^2d - 2pd - 2qd
2a - 2d = 2a(p + q) + d(p^2 + 2pq + q^2 -
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Pth term of an ap is a and qth term is b prove that the sum of its (p q)th?
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