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An average induced emf of 0.20 volt appears in a coil when the current in it is changed from 5 A in one direction to 5 A in the opposite direction in 0.20 seconds . Find the self inductance of coil ?
Verified Answer
An average induced emf of 0.20 volt appears in a coil when the current...
We know that ,,
Average dl/dt = -5-5/0.20 =>> - 50 A/s .
Using E = - L dl/dt
0.2 V = L ( 50 A/s )
L = 0.2V/50A/s
L =>> 4.0 mH .
This question is part of UPSC exam. View all Class 12 courses
Most Upvoted Answer
An average induced emf of 0.20 volt appears in a coil when the current...
Given data:
- Average induced emf (ε) = 0.20 V
- Current change rate (di/dt) = (5 A - (-5 A)) / 0.20 s = 50 A/s
Formula:
The relationship between self-inductance (L), current change rate (di/dt), and induced emf (ε) is given by the equation:
ε = -L * (di/dt)
Calculation:
Using the formula mentioned above, we can rearrange it to solve for the self-inductance (L):
L = -ε / (di/dt)
Substituting the given values into the equation:
L = -0.20 V / 50 A/s
Result:
The self-inductance of the coil is calculated as:
L = -0.20 V / 50 A/s
Explanation:
- The self-inductance of a coil is a measure of its ability to induce an emf in itself when the current flowing through it changes.
- When the current in the coil is changed, it creates a magnetic field around the coil.
- According to Faraday's law of electromagnetic induction, a changing magnetic field induces an emf in a nearby coil.
- The induced emf is given by the equation ε = -L * (di/dt), where ε is the induced emf, L is the self-inductance, and (di/dt) is the rate of change of current.
- In this problem, the average induced emf (ε) is given as 0.20 V, and the current change rate (di/dt) is calculated as 50 A/s.
- Using the formula, we can substitute these values to find the self-inductance (L) of the coil.
- The negative sign in the formula indicates that the induced emf opposes the change in current.
- Therefore, the self-inductance of the coil is calculated as L = -0.20 V / 50 A/s.
- Average induced emf (ε) = 0.20 V
- Current change rate (di/dt) = (5 A - (-5 A)) / 0.20 s = 50 A/s
Formula:
The relationship between self-inductance (L), current change rate (di/dt), and induced emf (ε) is given by the equation:
ε = -L * (di/dt)
Calculation:
Using the formula mentioned above, we can rearrange it to solve for the self-inductance (L):
L = -ε / (di/dt)
Substituting the given values into the equation:
L = -0.20 V / 50 A/s
Result:
The self-inductance of the coil is calculated as:
L = -0.20 V / 50 A/s
Explanation:
- The self-inductance of a coil is a measure of its ability to induce an emf in itself when the current flowing through it changes.
- When the current in the coil is changed, it creates a magnetic field around the coil.
- According to Faraday's law of electromagnetic induction, a changing magnetic field induces an emf in a nearby coil.
- The induced emf is given by the equation ε = -L * (di/dt), where ε is the induced emf, L is the self-inductance, and (di/dt) is the rate of change of current.
- In this problem, the average induced emf (ε) is given as 0.20 V, and the current change rate (di/dt) is calculated as 50 A/s.
- Using the formula, we can substitute these values to find the self-inductance (L) of the coil.
- The negative sign in the formula indicates that the induced emf opposes the change in current.
- Therefore, the self-inductance of the coil is calculated as L = -0.20 V / 50 A/s.
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An average induced emf of 0.20 volt appears in a coil when the current in it is changed from 5 A in one direction to 5 A in the opposite direction in 0.20 seconds . Find the self inductance of coil ?
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An average induced emf of 0.20 volt appears in a coil when the current in it is changed from 5 A in one direction to 5 A in the opposite direction in 0.20 seconds . Find the self inductance of coil ? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An average induced emf of 0.20 volt appears in a coil when the current in it is changed from 5 A in one direction to 5 A in the opposite direction in 0.20 seconds . Find the self inductance of coil ? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An average induced emf of 0.20 volt appears in a coil when the current in it is changed from 5 A in one direction to 5 A in the opposite direction in 0.20 seconds . Find the self inductance of coil ?.
An average induced emf of 0.20 volt appears in a coil when the current in it is changed from 5 A in one direction to 5 A in the opposite direction in 0.20 seconds . Find the self inductance of coil ? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An average induced emf of 0.20 volt appears in a coil when the current in it is changed from 5 A in one direction to 5 A in the opposite direction in 0.20 seconds . Find the self inductance of coil ? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An average induced emf of 0.20 volt appears in a coil when the current in it is changed from 5 A in one direction to 5 A in the opposite direction in 0.20 seconds . Find the self inductance of coil ?.
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