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In the above equation if moles required of S2O32– to titrate I2 was 2 then what were the moles of IO3 used:
IO3 + I + H+ → I2 + H2O, I2 + S2O32– → I + S4O62–
  • a)
    0.5
  • b)
    1.0
  • c)
    0.1
  • d)
    0.33
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
In the above equation if moles required of S2O32– to titrate I2 ...
Calculation of Moles of IO3 Used:

Given equation: IO3 + 5I + 6H+ → 3I2 + 3H2O

The balanced equation shows that 1 mole of IO3 reacts with 5 moles of I2.

Since 2 moles of S2O32 were used to titrate I2, we can say that 2 moles of I2 were present.

Therefore, the moles of IO3 used can be calculated as follows:

Moles of I2 = 2
Moles of IO3 = Moles of I2/5 = 2/5 = 0.4

Hence, the correct answer is option D, 0.33, which is the closest approximation to 0.4.
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Community Answer
In the above equation if moles required of S2O32– to titrate I2 ...
The balanced reactions are:
1)2IO3(-) + 12H(+)+10I(-)=6I2+6H2O.
2)I2+2S2O3^2(-)=2I(-) + S4O6^2(-)
From1,So 2 moles of IO3- = 6 moles of I2 So 1 mole of I2 =1/3 mole of IO3(-)......( 3)
From2,One mole of I2 = 2 mole of S2O3^2(-)......(4)
Combining 3 and 4,2 moles of S2O3^2(-) = 1/3 Mole of IO3(-) = 0.33 mole of IO3(-)
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In the above equation if moles required of S2O32– to titrate I2 was 2 then what were the moles of IO3– used:IO3– + I– + H+ → I2 + H2O, I2 + S2O32– → I– + S4O62–a)0.5b)1.0c)0.1d)0.33Correct answer is option 'D'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In the above equation if moles required of S2O32– to titrate I2 was 2 then what were the moles of IO3– used:IO3– + I– + H+ → I2 + H2O, I2 + S2O32– → I– + S4O62–a)0.5b)1.0c)0.1d)0.33Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the above equation if moles required of S2O32– to titrate I2 was 2 then what were the moles of IO3– used:IO3– + I– + H+ → I2 + H2O, I2 + S2O32– → I– + S4O62–a)0.5b)1.0c)0.1d)0.33Correct answer is option 'D'. Can you explain this answer?.
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