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A gaseous oxide contains 30.4% of nitrogen, one molecule of which contains one nitrogen atom. The density of the oxide relative to oxygen is:
  • a)
    0.94
  • b)
    1.44
  • c)
    1.50
  • d)
    3.0
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A gaseous oxide contains 30.4% of nitrogen, one molecule of which cont...
Nitrogen=30.4%
Oxygen=69.6%
Determine the chemical formula of the oxide
No.of moles of nitrogen=30.4/14=2.17
No.of moles of oxygen=69.6/16=4.35
Ratio of moles of nitrogen to oxygen is 2:4=1:2
Hence the formula of the oxide is NO2
Molar mass of the oxide=14+(2*16)=46
Relative density of oxygen=46/32=1.43
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Most Upvoted Answer
A gaseous oxide contains 30.4% of nitrogen, one molecule of which cont...
Solution:

To find the density of the gaseous oxide relative to oxygen, we need to compare the molar mass of the oxide to the molar mass of oxygen.

Given:
- The gaseous oxide contains 30.4% nitrogen.
- One molecule of the oxide contains one nitrogen atom.

Let's assume the molecular formula of the oxide is NxOy, where x is the number of nitrogen atoms and y is the number of oxygen atoms.

Step 1: Calculation of the molar mass of nitrogen:
The molar mass of nitrogen (N) is approximately 14.01 g/mol.

Step 2: Calculation of the molar mass of the oxide:
Since the oxide contains 30.4% nitrogen, it means that the remaining percentage (100% - 30.4% = 69.6%) is oxygen.

Let's assume the molar mass of the oxide is M.

The molar mass of the nitrogen atoms in the oxide is 30.4% of M.

Therefore, the molar mass of the oxygen atoms in the oxide is 69.6% of M.

The total molar mass of the oxide can be calculated as follows:

M = (30.4% of M) + (69.6% of M)

Simplifying the equation, we get:

M = 0.304M + 0.696M

M = 1M

So, the molar mass of the oxide (M) is equal to 1 times the molar mass of oxygen.

Step 3: Calculation of the density of the oxide relative to oxygen:
The density of a gas can be calculated using the ideal gas law equation:

Density = (molar mass) / (molar volume)

Since we are comparing the density of the oxide to oxygen, we can write:

Density of the oxide relative to oxygen = (molar mass of the oxide) / (molar mass of oxygen)

Using the values we obtained earlier:

Density of the oxide relative to oxygen = M / (molar mass of oxygen)

Substituting the value of M (molar mass of the oxide) from Step 2:

Density of the oxide relative to oxygen = 1 / (molar mass of oxygen)

The molar mass of oxygen is approximately 16.00 g/mol.

Therefore:

Density of the oxide relative to oxygen = 1 / 16.00

Density of the oxide relative to oxygen = 0.0625 g/mL

Since the density is expressed in grams per milliliter (g/mL), we need to convert it to grams per liter (g/L):

Density of the oxide relative to oxygen = 0.0625 g/mL x 1000 mL/L

Density of the oxide relative to oxygen = 62.5 g/L

The density of the oxide relative to oxygen is 62.5 g/L.

Comparing the options given, the correct answer is option 'B' - 1.44
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A gaseous oxide contains 30.4% of nitrogen, one molecule of which contains one nitrogen atom. The density of the oxide relative to oxygen is:a)0.94b)1.44c)1.50d)3.0Correct answer is option 'B'. Can you explain this answer?
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