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A metal ball weighing 200g is balanced in mid air by throwing 40 balls per second vertically upwards from below. After collision, balls rebound with the same speed. What is the speed with which the balls strike the plate?(given: mass of each ball= 200g)(g=9.8 m/s^2)
Verified Answer
A metal ball weighing 200g is balanced in mid air by throwing 40 balls...
Given : Mass of Plate = 0.2 Kg
Mass of Each Ball = 0.2 Kg
No. of Ball thrown = 40
The plate is balanced so the force exterted by plate is equal to the force of 40 balls
= Mg = 40 x mv/t
= 0.2 x 10 = 40 x 0.2 x v/1(t=1 sec)
= v = 0.25 m/sec
This question is part of UPSC exam. View all Class 9 courses
Most Upvoted Answer
A metal ball weighing 200g is balanced in mid air by throwing 40 balls...
Problem:
A metal ball weighing 200g is balanced in mid-air by throwing 40 balls per second vertically upwards from below. After collision, balls rebound with the same speed. What is the speed with which the balls strike the plate? (Given: mass of each ball = 200g, g = 9.8 m/s^2)
Solution:
Step 1: Understanding the situation
- A metal ball weighing 200g is balanced in mid-air, which means the net force acting on it is zero.
- 40 balls per second are thrown vertically upwards from below.
- After collision, the balls rebound with the same speed.
Step 2: Analyzing the forces involved
- The metal ball is balanced, so the net force acting on it is zero. This implies that the weight of the ball is balanced by the force exerted by the balls thrown from below.
- The weight of the ball can be calculated using the formula:
Weight = mass * acceleration due to gravity (W = m * g)
Weight = 0.2 kg * 9.8 m/s^2 = 1.96 N
Step 3: Calculating the force exerted by the thrown balls
- The force exerted by the thrown balls can be calculated using Newton's second law of motion:
Force = mass * acceleration (F = m * a)
Since the balls rebound with the same speed, their acceleration is the same as the acceleration due to gravity, which is 9.8 m/s^2.
Force = 0.2 kg * 9.8 m/s^2 = 1.96 N
Step 4: Calculating the speed of the balls
- The force exerted by the thrown balls is equal to the weight of the metal ball, so we can equate the two forces:
Force = Weight
1.96 N = 1.96 N
This means that the force exerted by the balls is equal to the weight of the metal ball.
Step 5: Conclusion
- Since the force exerted by the thrown balls is equal to the weight of the metal ball, the speed with which the balls strike the plate is the same as the speed at which they were thrown upwards, which is equal to the acceleration due to gravity, 9.8 m/s^2.
Therefore, the speed with which the balls strike the plate is 9.8 m/s.
A metal ball weighing 200g is balanced in mid-air by throwing 40 balls per second vertically upwards from below. After collision, balls rebound with the same speed. What is the speed with which the balls strike the plate? (Given: mass of each ball = 200g, g = 9.8 m/s^2)
Solution:
Step 1: Understanding the situation
- A metal ball weighing 200g is balanced in mid-air, which means the net force acting on it is zero.
- 40 balls per second are thrown vertically upwards from below.
- After collision, the balls rebound with the same speed.
Step 2: Analyzing the forces involved
- The metal ball is balanced, so the net force acting on it is zero. This implies that the weight of the ball is balanced by the force exerted by the balls thrown from below.
- The weight of the ball can be calculated using the formula:
Weight = mass * acceleration due to gravity (W = m * g)
Weight = 0.2 kg * 9.8 m/s^2 = 1.96 N
Step 3: Calculating the force exerted by the thrown balls
- The force exerted by the thrown balls can be calculated using Newton's second law of motion:
Force = mass * acceleration (F = m * a)
Since the balls rebound with the same speed, their acceleration is the same as the acceleration due to gravity, which is 9.8 m/s^2.
Force = 0.2 kg * 9.8 m/s^2 = 1.96 N
Step 4: Calculating the speed of the balls
- The force exerted by the thrown balls is equal to the weight of the metal ball, so we can equate the two forces:
Force = Weight
1.96 N = 1.96 N
This means that the force exerted by the balls is equal to the weight of the metal ball.
Step 5: Conclusion
- Since the force exerted by the thrown balls is equal to the weight of the metal ball, the speed with which the balls strike the plate is the same as the speed at which they were thrown upwards, which is equal to the acceleration due to gravity, 9.8 m/s^2.
Therefore, the speed with which the balls strike the plate is 9.8 m/s.
Community Answer
A metal ball weighing 200g is balanced in mid air by throwing 40 balls...
A bomb initially at rest at a height of 40m above the ground suddenly explodes into two identical fragments.one of them starts moving vertically downwards with an initial speed of 10 metre per second. if acceleration due to gravity is 10 metre per second, what is the separation between the fragaments 2s after the explosion
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A metal ball weighing 200g is balanced in mid air by throwing 40 balls per second vertically upwards from below. After collision, balls rebound with the same speed. What is the speed with which the balls strike the plate?(given: mass of each ball= 200g)(g=9.8 m/s^2)
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A metal ball weighing 200g is balanced in mid air by throwing 40 balls per second vertically upwards from below. After collision, balls rebound with the same speed. What is the speed with which the balls strike the plate?(given: mass of each ball= 200g)(g=9.8 m/s^2) for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A metal ball weighing 200g is balanced in mid air by throwing 40 balls per second vertically upwards from below. After collision, balls rebound with the same speed. What is the speed with which the balls strike the plate?(given: mass of each ball= 200g)(g=9.8 m/s^2) covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal ball weighing 200g is balanced in mid air by throwing 40 balls per second vertically upwards from below. After collision, balls rebound with the same speed. What is the speed with which the balls strike the plate?(given: mass of each ball= 200g)(g=9.8 m/s^2).
A metal ball weighing 200g is balanced in mid air by throwing 40 balls per second vertically upwards from below. After collision, balls rebound with the same speed. What is the speed with which the balls strike the plate?(given: mass of each ball= 200g)(g=9.8 m/s^2) for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A metal ball weighing 200g is balanced in mid air by throwing 40 balls per second vertically upwards from below. After collision, balls rebound with the same speed. What is the speed with which the balls strike the plate?(given: mass of each ball= 200g)(g=9.8 m/s^2) covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A metal ball weighing 200g is balanced in mid air by throwing 40 balls per second vertically upwards from below. After collision, balls rebound with the same speed. What is the speed with which the balls strike the plate?(given: mass of each ball= 200g)(g=9.8 m/s^2).
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