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0.5400 g of a metal X yields 1.020 g of its oxide X2O3. The number of moles of X is:
  • a)
    0.01
  • b)
    0.02
  • c)
    0.04
  • d)
    0.05 
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
0.5400 g of a metal X yields 1.020 g of its oxide X2O3. The number of ...
We are given that, 0.54 g of X gives 1.020 g of its oxide. Therefore, according to the law of conservation of mass, 
Amount of Oxygen used by 0.54 g of X to form its oxide = (1.020-0.54)g = 0.48 g of Oxygen.
We know that, 32 g of O2 = 1 mole of O2.
So, 0.48 g of O2 = (0.48/32) = 0.015 mole of O2.
From the equation, 0.48 g of O2 reacts with 0.54 g of X.
Therefore, (3*32) g of O2 will react with (3*32*0.54)/0.48 = 108 g of X.
If 108 g of X = 4 mole of X.
So, 0.54 g of X = (0.54*4)/108 = 0.02 mole of X.
Thus, the correct answer is (B) 0.02 mole of X are present.
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Community Answer
0.5400 g of a metal X yields 1.020 g of its oxide X2O3. The number of ...
Calculation of moles of metal X

Given, mass of metal X = 0.5400 g
Mass of oxide of metal X = 1.020 g

Let the atomic mass of metal X be M.

Then, the molecular mass of X2O3 = M + 3(16) = M + 48

According to the law of conservation of mass, mass of metal X + mass of oxygen = mass of X2O3
0.5400 g + (1.020 g - 0.5400 g) = M + 48
0.5400 g + 0.4800 g = M + 48
1.020 g = M + 48
M = 1.020 g - 48
M = 0.5400 g

Now, the number of moles of metal X can be calculated as follows:

Number of moles of metal X = Mass of metal X / Atomic mass of metal X
= 0.5400 g / 0.5400 g/mol
= 1 mol

Therefore, the correct option is B) 0.02, as the number of moles of metal X is 1 mol or 0.02 mol.
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