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In borazine (B3N3H6) molecule, the number of isomers which are possible of its disubstituted borazine molecule of the formula [B3N3H4X2] without changing its ring structure is:
- a)One
- b)Two
- c)Four
- d)Six
Correct answer is option 'A'. Can you explain this answer?
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In borazine (B3N3H6) molecule, the number of isomers which are possibl...
if you put a=b=pi/4, then c=0 and tan a = 1.
Hence, (b) or (c) can be the correct answers.
Now, let us suppose that a = pi/8, then b = 3pi/8. Then c = - pi/4.
Then ‘tan b + tan c’ will not fit. Hence, (c) is the correct answer.
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In borazine (B3N3H6) molecule, the number of isomers which are possibl...
Possible Isomers of Disubstituted Borazine Molecule
Borazine Molecule: Borazine is a heterocyclic compound with the formula B3N3H6. It consists of a six-membered ring of alternating boron and nitrogen atoms, with each boron atom also bonded to a hydrogen atom.
Disubstituted Borazine Molecule: A disubstituted borazine molecule of the formula [B3N3H4X2] is formed by replacing two hydrogen atoms with two different substituents (X). The ring structure of borazine should remain unchanged in this process.
Number of Isomers: The number of isomers possible for a disubstituted borazine molecule depends on the number of different ways the two substituents can be arranged on the ring. Since borazine has a planar hexagonal ring, the two substituents can be arranged in three different ways:
1. Adjacent: The two substituents can be placed on adjacent carbon atoms of the ring, resulting in only one possible isomer.
2. Opposite: The two substituents can be placed on opposite carbon atoms of the ring, resulting in a mirror image isomer.
3. Alternate: The two substituents can be placed on alternate carbon atoms of the ring, resulting in two additional isomers that are also mirror images of each other.
Therefore, the total number of isomers possible for a disubstituted borazine molecule is only one, as the adjacent arrangement is the only possible isomer without changing the ring structure.
Borazine Molecule: Borazine is a heterocyclic compound with the formula B3N3H6. It consists of a six-membered ring of alternating boron and nitrogen atoms, with each boron atom also bonded to a hydrogen atom.
Disubstituted Borazine Molecule: A disubstituted borazine molecule of the formula [B3N3H4X2] is formed by replacing two hydrogen atoms with two different substituents (X). The ring structure of borazine should remain unchanged in this process.
Number of Isomers: The number of isomers possible for a disubstituted borazine molecule depends on the number of different ways the two substituents can be arranged on the ring. Since borazine has a planar hexagonal ring, the two substituents can be arranged in three different ways:
1. Adjacent: The two substituents can be placed on adjacent carbon atoms of the ring, resulting in only one possible isomer.
2. Opposite: The two substituents can be placed on opposite carbon atoms of the ring, resulting in a mirror image isomer.
3. Alternate: The two substituents can be placed on alternate carbon atoms of the ring, resulting in two additional isomers that are also mirror images of each other.
Therefore, the total number of isomers possible for a disubstituted borazine molecule is only one, as the adjacent arrangement is the only possible isomer without changing the ring structure.
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In borazine (B3N3H6) molecule, the number of isomers which are possibl...
4 is possible
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In borazine (B3N3H6) molecule, the number of isomers which are possible of its disubstituted borazine molecule of the formula [B3N3H4X2] without changing its ring structure is:a)Oneb)Twoc)Fourd)SixCorrect answer is option 'A'. Can you explain this answer?
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In borazine (B3N3H6) molecule, the number of isomers which are possible of its disubstituted borazine molecule of the formula [B3N3H4X2] without changing its ring structure is:a)Oneb)Twoc)Fourd)SixCorrect answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In borazine (B3N3H6) molecule, the number of isomers which are possible of its disubstituted borazine molecule of the formula [B3N3H4X2] without changing its ring structure is:a)Oneb)Twoc)Fourd)SixCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In borazine (B3N3H6) molecule, the number of isomers which are possible of its disubstituted borazine molecule of the formula [B3N3H4X2] without changing its ring structure is:a)Oneb)Twoc)Fourd)SixCorrect answer is option 'A'. Can you explain this answer?.
In borazine (B3N3H6) molecule, the number of isomers which are possible of its disubstituted borazine molecule of the formula [B3N3H4X2] without changing its ring structure is:a)Oneb)Twoc)Fourd)SixCorrect answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In borazine (B3N3H6) molecule, the number of isomers which are possible of its disubstituted borazine molecule of the formula [B3N3H4X2] without changing its ring structure is:a)Oneb)Twoc)Fourd)SixCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In borazine (B3N3H6) molecule, the number of isomers which are possible of its disubstituted borazine molecule of the formula [B3N3H4X2] without changing its ring structure is:a)Oneb)Twoc)Fourd)SixCorrect answer is option 'A'. Can you explain this answer?.
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