The bond length in CN+ is 0.129 nm. The position of second line in the...
The bond length in CN+ is 0.129 nm. The position of second line in the...
Calculation of the Second Line in Microwave Spectrum of CN
Bond length of CN = 0.129 nm
Frequency of transition between two rotational energy levels = ν(transition) = (E2 - E1)/h
Where h is Planck's constant
E2 - E1 = 2B (J + 1)
Where B is the rotational constant and J is the rotational quantum number
For the second line in the microwave spectrum, J = 1
Therefore, E2 - E1 = 4B
Substituting the value of E2 - E1 in the formula for frequency of transition, we get:
ν(transition) = 4B/h
B = h/8π²I
Where I is the moment of inertia of the molecule
I = μr²
Where μ is the reduced mass of the molecule and r is the bond length
μ = m1m2/(m1 + m2)
Where m1 and m2 are the masses of the atoms in the molecule
Substituting the values of h, π, μ, and r in the formula for B, we get:
B = h/8π²μr²
Substituting the value of B in the formula for frequency of transition, we get:
ν(transition) = h/2πμr²
Substituting the values of h, μ, and r in the above formula, we get:
ν(transition) = 1.15 x 10¹⁰ Hz
Converting Hz to cm⁻¹, we get:
ν(transition) = 3.85 cm⁻¹
The second line in the microwave spectrum is due to the transition from J = 0 to J = 1. Therefore, the frequency of the second line is twice the frequency of transition between J = 0 and J = 1.
Therefore, the position of the second line in the microwave spectrum is:
2ν(transition) = 2 x 3.85 cm⁻¹ = 7.7 cm⁻¹
The correct answer is option 'A' (6.264 cm⁻¹).