How many grams of concentrated nitric acid solution should be used to ...
The required number of moles=( 250/1000)x2
=0.5 moles
(no. of moles=molarity x volume)
so,required mass of HNO3=0.5x63
=31.5 grams
(given mass=no. of moles x molar mass)
Given,
70 grams of HNO3 are present in 100 grams of the solution
so,1 gram will be present in 100/70 grams of solution
hence 31.5 grams will be present in (100/70)x31.5 grams of solution.
so amount of concentrated nitric acid solution used is 45 grams.
How many grams of concentrated nitric acid solution should be used to ...
Calculating the amount of concentrated nitric acid solution needed:
- Given:
- Target concentration of HNO3: 2.0 M
- Volume needed: 250 mL
- Concentrated acid concentration: 70%
- Formula to calculate the amount of concentrated acid needed:
- C1V1 = C2V2
- Where:
- C1 = Concentration of concentrated acid (unknown)
- V1 = Volume of concentrated acid (unknown)
- C2 = Target concentration of HNO3 (2.0 M)
- V2 = Volume needed (250 mL)
- Let's solve for C1:
- 0.70 * V1 = 2.0 M * 250 mL
- V1 = (2.0 M * 250 mL) / 0.70
- V1 = 714.29 mL
- Therefore, you would need 714.29 mL of the 70% concentrated nitric acid solution to prepare 250 mL of 2.0 M HNO3.
Converting mL to grams:
- To convert the volume (mL) to grams, you would need to use the density of the concentrated nitric acid solution.
- The density of concentrated nitric acid is approximately 1.41 g/mL.
- Therefore, to calculate the mass of the concentrated acid needed:
- Mass = Volume * Density
- Mass = 714.29 mL * 1.41 g/mL
- Mass ≈ 1007.14 grams
- Hence, you would need approximately 1007.14 grams of the 70% concentrated nitric acid solution to prepare 250 mL of 2.0 M HNO3.