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One mole of a monoatomic real gas sat isfied the equation p(V – b) = RT where b is a constant. The relationship of interatomic potential V ( r) and interatomic distance r for the gas is given by:
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
One mole of a monoatomic real gas sat isfied the equation p(V – ...
For a real gas
(P + an2/V2)(V – nb) = nRT
ATQ: P (V-nb) = RT
The extra term “an2/V2” comes because of the attractive forces, hence with a certain decrease in r V(r) remains constant.
But after a huge decrease repulsive forces will dominate and hence V(r) will increase abruptly.
Hence C is correct.
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Most Upvoted Answer
One mole of a monoatomic real gas sat isfied the equation p(V – ...
  At large inter-ionic distances (because a → 0) the P.E. would remain constant.
  However, when r → 0; repulsion would suddenly increase.
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Community Answer
One mole of a monoatomic real gas sat isfied the equation p(V – ...
For a real gas
(P + an2/V2)(V – nb) = nRT
ATQ: P (V-nb) = RT
The extra term “an2/V2” comes because of the attractive forces, hence with a certain decrease in r V(r) remains constant.
But after a huge decrease repulsive forces will dominate and hence V(r) will increase abruptly.
Hence C is correct.
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