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One end of a Nichrome wire of length 2L and cross-sectional area A is attatched to an end of another Nichrome wire of length L and cross-sectional area 2A. If the free end of the longer wire is at an electric potential of 8.0 volts, and the free end of the shorter wire is at an electric potential of 1.0 volt, the potential at the junction of the two wires is equal to
- a)2.4 V
- b)3.2 V
- c)4.5 V
- d)5.6 V
Correct answer is option 'A'. Can you explain this answer?
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One end of a Nichrome wire of length 2L and cross-sectional area A is ...
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One end of a Nichrome wire of length 2L and cross-sectional area A is ...
Given Data:
- Length of longer wire (2L) = 2L
- Cross-sectional area of longer wire (A) = A
- Length of shorter wire (L) = L
- Cross-sectional area of shorter wire (2A) = 2A
- Potential at the free end of the longer wire = 8.0 V
- Potential at the free end of the shorter wire = 1.0 V
Explanation:
Step 1: Find the Resistance of each Wire
- The resistance of a wire is given by R = ρ * (L/A), where ρ is the resistivity of the material.
- Let's assume the resistivity ρ is the same for both wires.
- For the longer wire: R1 = ρ * (2L/A)
- For the shorter wire: R2 = ρ * (L/2A)
Step 2: Find the Potential at the Junction
- Let V1 be the potential at the junction.
- Using the voltage divider rule, we can write:
- (8 - V1) / (R1 + R2) = (V1 - 1) / R2
- Substituting the values of R1 and R2:
- (8 - V1) / (2L/A + L/2A) = (V1 - 1) / (L/2A)
- Simplifying the equation, we get:
- 4(8 - V1) = 3(V1 - 1)
- Solving for V1, we get V1 = 2.4 V
Therefore, the potential at the junction of the two wires is 2.4 V. Hence, option 'A' is the correct answer.
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One end of a Nichrome wire of length 2L and cross-sectional area A is attatched to an end of another Nichrome wire of length L and cross-sectional area 2A. If the free end of the longer wire is at an electric potential of 8.0 volts, and the free end of the shorter wire is at an electric potential of 1.0 volt, the potential at the junction of the two wires is equal toa)2.4 Vb)3.2 Vc)4.5 Vd)5.6 VCorrect answer is option 'A'. Can you explain this answer?
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One end of a Nichrome wire of length 2L and cross-sectional area A is attatched to an end of another Nichrome wire of length L and cross-sectional area 2A. If the free end of the longer wire is at an electric potential of 8.0 volts, and the free end of the shorter wire is at an electric potential of 1.0 volt, the potential at the junction of the two wires is equal toa)2.4 Vb)3.2 Vc)4.5 Vd)5.6 VCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One end of a Nichrome wire of length 2L and cross-sectional area A is attatched to an end of another Nichrome wire of length L and cross-sectional area 2A. If the free end of the longer wire is at an electric potential of 8.0 volts, and the free end of the shorter wire is at an electric potential of 1.0 volt, the potential at the junction of the two wires is equal toa)2.4 Vb)3.2 Vc)4.5 Vd)5.6 VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One end of a Nichrome wire of length 2L and cross-sectional area A is attatched to an end of another Nichrome wire of length L and cross-sectional area 2A. If the free end of the longer wire is at an electric potential of 8.0 volts, and the free end of the shorter wire is at an electric potential of 1.0 volt, the potential at the junction of the two wires is equal toa)2.4 Vb)3.2 Vc)4.5 Vd)5.6 VCorrect answer is option 'A'. Can you explain this answer?.
One end of a Nichrome wire of length 2L and cross-sectional area A is attatched to an end of another Nichrome wire of length L and cross-sectional area 2A. If the free end of the longer wire is at an electric potential of 8.0 volts, and the free end of the shorter wire is at an electric potential of 1.0 volt, the potential at the junction of the two wires is equal toa)2.4 Vb)3.2 Vc)4.5 Vd)5.6 VCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about One end of a Nichrome wire of length 2L and cross-sectional area A is attatched to an end of another Nichrome wire of length L and cross-sectional area 2A. If the free end of the longer wire is at an electric potential of 8.0 volts, and the free end of the shorter wire is at an electric potential of 1.0 volt, the potential at the junction of the two wires is equal toa)2.4 Vb)3.2 Vc)4.5 Vd)5.6 VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One end of a Nichrome wire of length 2L and cross-sectional area A is attatched to an end of another Nichrome wire of length L and cross-sectional area 2A. If the free end of the longer wire is at an electric potential of 8.0 volts, and the free end of the shorter wire is at an electric potential of 1.0 volt, the potential at the junction of the two wires is equal toa)2.4 Vb)3.2 Vc)4.5 Vd)5.6 VCorrect answer is option 'A'. Can you explain this answer?.
Solutions for One end of a Nichrome wire of length 2L and cross-sectional area A is attatched to an end of another Nichrome wire of length L and cross-sectional area 2A. If the free end of the longer wire is at an electric potential of 8.0 volts, and the free end of the shorter wire is at an electric potential of 1.0 volt, the potential at the junction of the two wires is equal toa)2.4 Vb)3.2 Vc)4.5 Vd)5.6 VCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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