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The integrating factor of differential equation is :
  • a)
    log (1/x)
  • b)
    log x2
  • c)
    log x
  • d)
    -log x
Correct answer is option 'C'. Can you explain this answer?
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The integrating factor ofdifferential equationis :a)log (1/x)b)log x2c...
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The integrating factor ofdifferential equationis :a)log (1/x)b)log x2c...
xlog x dy/dx + y = 2logx
⇒ dy/dx + y/(xlogx) = 2/x...(1)
Put P = 1/x logx
⇒∫PdP = ∫1/x logx dx 
= log(logx)
∴ I.F.= e∫PdP = elog(logx)
 = logx
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The integrating factor ofdifferential equationis :a)log (1/x)b)log x2c)log xd)-log xCorrect answer is option 'C'. Can you explain this answer?
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