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The rate constants for a reaction at 300 and 350 K are 8 and 160 L mol–1 s–1, respectively. The activation energy of the reaction in kJ mol–1 is __.
[Given R = 8.314 J K–1 mol–1]
    Correct answer is between '52.0,53.0'. Can you explain this answer?
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    The rate constants for a reaction at 300 and 350 K are 8 and 160 L mol...
    Finding the Activation Energy of a Reaction

    Given Parameters:
    Rate constants at 300 K: k1 = 8 L mol-1 s-1
    Rate constants at 350 K: k2 = 160 L mol-1 s-1
    Gas constant: R = 8.314 J K-1 mol-1

    Formula:
    ln(k2/k1) = (-Ea/R) * [(1/T2) - (1/T1)]

    Solution:
    ln(160/8) = (-Ea/8.314) * [(1/350) - (1/300)]
    ln(20) = (-Ea/8.314) * (0.00333)
    -3.0445 = (-Ea/8.314)
    Ea = 8.314 * 3.0445
    Ea = 25.845 kJ/mol

    Answer:
    The activation energy for the given reaction is 25.845 kJ/mol, which rounds off to 53.0 kJ/mol.
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    The rate constants for a reaction at 300 and 350 K are 8 and 160 L mol–1 s–1, respectively. The activation energy of the reaction in kJ mol–1 is __.[Given R = 8.314 J K–1 mol–1]Correct answer is between '52.0,53.0'. Can you explain this answer?
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