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The language 
  • a)
    regular
  • b)
    context-free but not regular
  • c)
    context-sensitive but not context free
  • d)
    type-0 but not context sensitive
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The language a)regularb)context-free but not regularc)context-sensitiv...
Language is not regular bcoz we need to match count of c's is equal to count of b's + count of a's
and that can implement by PDA
∂(q0,a,^)= (q0,a) [ push a in stack, as per language a comes first]
∂(q0,a,a)= (q0,aa) [push all a's into stack]
∂(q0,b,a) = (q1,ba) [push b in stack, state change to q1 that sure b comes after a]
∂(q1,b,b)=(q1,bb) [push all b's in stack]
∂(q1,c,b) = (q2,^) [ pop one b for one c]
∂(q2,c,b) = (q2,c) [ pop one b's for each c and continue same ]
∂(q2,c,a) = (q3,^) [ pop one a for one c , when there is no more b in stack]
∂(q3,c,a) = (q3,^) [pop one a for each c and continue same]
∂(q3,^,^) = (qf,^) [ if sum of c's is sum of a's and b's then stack will be empty when there is no c in input]
Note :1. state changes make sure b's comes after a and c's comes after b's]
 
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Most Upvoted Answer
The language a)regularb)context-free but not regularc)context-sensitiv...
Option B coz here exponential terms are not equal to 0.
so,answer is B..
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Community Answer
The language a)regularb)context-free but not regularc)context-sensitiv...
The language a power m b power n c power m+n and m,n put of big 1 is


context - free but not regular
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