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Passage lIOne of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and carbon dioxide.Initial partial pressureCO(g) = 1.40 atmCO2(g) = 0.80 atmQ.When equilibrium is attained,a) = Pco = 1-74 atmb) = Pco = 0.46 atmc) = 0-46 atm, pco = 1.74 atmd)= 1.74 atm, pco = 0.46 atmCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Passage lIOne of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and carbon dioxide.Initial partial pressureCO(g) = 1.40 atmCO2(g) = 0.80 atmQ.When equilibrium is attained,a) = Pco = 1-74 atmb) = Pco = 0.46 atmc) = 0-46 atm, pco = 1.74 atmd)= 1.74 atm, pco = 0.46 atmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Passage lIOne of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and carbon dioxide.Initial partial pressureCO(g) = 1.40 atmCO2(g) = 0.80 atmQ.When equilibrium is attained,a) = Pco = 1-74 atmb) = Pco = 0.46 atmc) = 0-46 atm, pco = 1.74 atmd)= 1.74 atm, pco = 0.46 atmCorrect answer is option 'C'. Can you explain this answer?.

Solutions for Passage lIOne of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and carbon dioxide.Initial partial pressureCO(g) = 1.40 atmCO2(g) = 0.80 atmQ.When equilibrium is attained,a) = Pco = 1-74 atmb) = Pco = 0.46 atmc) = 0-46 atm, pco = 1.74 atmd)= 1.74 atm, pco = 0.46 atmCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

Here you can find the meaning of Passage lIOne of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and carbon dioxide.Initial partial pressureCO(g) = 1.40 atmCO2(g) = 0.80 atmQ.When equilibrium is attained,a) = Pco = 1-74 atmb) = Pco = 0.46 atmc) = 0-46 atm, pco = 1.74 atmd)= 1.74 atm, pco = 0.46 atmCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Passage lIOne of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and carbon dioxide.Initial partial pressureCO(g) = 1.40 atmCO2(g) = 0.80 atmQ.When equilibrium is attained,a) = Pco = 1-74 atmb) = Pco = 0.46 atmc) = 0-46 atm, pco = 1.74 atmd)= 1.74 atm, pco = 0.46 atmCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for Passage lIOne of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and carbon dioxide.Initial partial pressureCO(g) = 1.40 atmCO2(g) = 0.80 atmQ.When equilibrium is attained,a) = Pco = 1-74 atmb) = Pco = 0.46 atmc) = 0-46 atm, pco = 1.74 atmd)= 1.74 atm, pco = 0.46 atmCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of Passage lIOne of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and carbon dioxide.Initial partial pressureCO(g) = 1.40 atmCO2(g) = 0.80 atmQ.When equilibrium is attained,a) = Pco = 1-74 atmb) = Pco = 0.46 atmc) = 0-46 atm, pco = 1.74 atmd)= 1.74 atm, pco = 0.46 atmCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Passage lIOne of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and carbon dioxide.Initial partial pressureCO(g) = 1.40 atmCO2(g) = 0.80 atmQ.When equilibrium is attained,a) = Pco = 1-74 atmb) = Pco = 0.46 atmc) = 0-46 atm, pco = 1.74 atmd)= 1.74 atm, pco = 0.46 atmCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 11 tests.