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Given that
(i) C + O₂ → CO₂ ; ∆Ho = − xkJ,
(ii) 2CO + O₂ → 2CO₂ ; ∆Ho = −ykJ .
The enthalpy of formation of carbon monoxide will be
  • a)
    y-2x
  • b)
    2x-y/2
  • c)
    y-2x/2
  • d)
    2x-y
Correct answer is option 'C'. Can you explain this answer?
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Given that(i) C + O₂ → CO₂ ; ∆Ho= − xkJ,(...
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Given that(i) C + O₂ → CO₂ ; ∆Ho= − xkJ,(...
(i) Carbon is located to the left of oxygen on the periodic table, so carbon has a lower atomic number than oxygen. This means that carbon has fewer protons in its nucleus than oxygen.

(ii) Oxygen has a higher electronegativity than carbon. This means that oxygen has a greater ability to attract electrons towards itself in a chemical bond compared to carbon.

(iii) Carbon and oxygen can form a covalent bond between them. In a covalent bond, electrons are shared between the atoms involved. In the case of carbon and oxygen, carbon can share one electron with oxygen to form a covalent bond.

(iv) The Lewis structure of carbon dioxide (CO2) shows that carbon is bonded to two oxygen atoms. Each oxygen atom shares two electrons with carbon, resulting in double bonds between carbon and oxygen.

(v) Carbon dioxide is a linear molecule, meaning that the carbon and oxygen atoms are arranged in a straight line. This is because the carbon-oxygen double bonds repel each other, causing the molecule to adopt a linear shape to minimize electron-electron repulsion.
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Given that(i) C + O₂ → CO₂ ; ∆Ho= − xkJ,(ii) 2CO + O₂ → 2CO₂ ; ∆Ho= −ykJ .The enthalpy of formation of carbon monoxide will bea)y-2xb)2x-y/2c)y-2x/2d)2x-yCorrect answer is option 'C'. Can you explain this answer?
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Given that(i) C + O₂ → CO₂ ; ∆Ho= − xkJ,(ii) 2CO + O₂ → 2CO₂ ; ∆Ho= −ykJ .The enthalpy of formation of carbon monoxide will bea)y-2xb)2x-y/2c)y-2x/2d)2x-yCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Given that(i) C + O₂ → CO₂ ; ∆Ho= − xkJ,(ii) 2CO + O₂ → 2CO₂ ; ∆Ho= −ykJ .The enthalpy of formation of carbon monoxide will bea)y-2xb)2x-y/2c)y-2x/2d)2x-yCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given that(i) C + O₂ → CO₂ ; ∆Ho= − xkJ,(ii) 2CO + O₂ → 2CO₂ ; ∆Ho= −ykJ .The enthalpy of formation of carbon monoxide will bea)y-2xb)2x-y/2c)y-2x/2d)2x-yCorrect answer is option 'C'. Can you explain this answer?.
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