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At 1400 K, Kc= 2.5x10 +3 for the reaction CH4(g) + 2H2S(g) CS2(g) + 4H2(g) . A 10.0L reaction vessel at 1400 K contains 2.00 mole of CH4, 3.0 mol of CS2, 3.0 mole of H2 and 4.0 mole of H2S. Then
- a)This reaction, is at equilibrium with above concentrations.
- b)The reaction will proceed in forward direction to reach equilibrium.
- c)The reaction will proceed in backward direction to reach equilibrium.
- d)The information is insufficient to decide the direction of progress of reaction.
Correct answer is option 'C'. Can you explain this answer?
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At 1400 K, Kc= 2.5x10 +3 for the reaction CH4(g) + 2H2S(g) CS2(g) + 4H...
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At 1400 K, Kc= 2.5x10 +3 for the reaction CH4(g) + 2H2S(g) CS2(g) + 4H...
Explanation:
To determine the direction of the reaction, we can compare the given initial concentrations with the equilibrium constant.
Step 1: Write the balanced chemical equation:
CH4(g) + 2H2S(g) ⇌ CS2(g) + 4H2(g)
Step 2: Write the expression for the equilibrium constant:
Kc = [CS2] / ([CH4] * [H2S]^2 * [H2]^4)
Step 3: Calculate the initial and final concentrations:
Initial concentrations:
[CH4] = 2.00 mol / 10.0 L = 0.20 M
[H2S] = 4.0 mol / 10.0 L = 0.40 M
[CS2] = 3.0 mol / 10.0 L = 0.30 M
[H2] = 3.0 mol / 10.0 L = 0.30 M
Final concentrations:
[CH4] = (2.00 - x) mol / (10.0 + x) L
[H2S] = (4.0 - 2x) mol / (10.0 + x) L
[CS2] = (3.0 + x) mol / (10.0 + x) L
[H2] = (3.0 + 4x) mol / (10.0 + x) L
Step 4: Substitute values into the equilibrium constant expression:
Kc = (0.30 + x) / [(0.20)(0.40 - 2x)(0.30 + 4x)^4]
Step 5: Determine the direction of the reaction:
Since Kc is given as 2.5x10^3, we can set up an equation and solve for x:
2.5x10^3 = (0.30 + x) / [(0.20)(0.40 - 2x)(0.30 + 4x)^4]
Solving this equation for x will give us the value of x, which represents the change in concentrations from the initial to the equilibrium state. If x is positive, it means the reaction has proceeded in the forward direction to reach equilibrium. If x is negative, it means the reaction has proceeded in the backward direction to reach equilibrium.
Conclusion:
The correct answer is option 'C'. The reaction will proceed in the backward direction to reach equilibrium.
To determine the direction of the reaction, we can compare the given initial concentrations with the equilibrium constant.
Step 1: Write the balanced chemical equation:
CH4(g) + 2H2S(g) ⇌ CS2(g) + 4H2(g)
Step 2: Write the expression for the equilibrium constant:
Kc = [CS2] / ([CH4] * [H2S]^2 * [H2]^4)
Step 3: Calculate the initial and final concentrations:
Initial concentrations:
[CH4] = 2.00 mol / 10.0 L = 0.20 M
[H2S] = 4.0 mol / 10.0 L = 0.40 M
[CS2] = 3.0 mol / 10.0 L = 0.30 M
[H2] = 3.0 mol / 10.0 L = 0.30 M
Final concentrations:
[CH4] = (2.00 - x) mol / (10.0 + x) L
[H2S] = (4.0 - 2x) mol / (10.0 + x) L
[CS2] = (3.0 + x) mol / (10.0 + x) L
[H2] = (3.0 + 4x) mol / (10.0 + x) L
Step 4: Substitute values into the equilibrium constant expression:
Kc = (0.30 + x) / [(0.20)(0.40 - 2x)(0.30 + 4x)^4]
Step 5: Determine the direction of the reaction:
Since Kc is given as 2.5x10^3, we can set up an equation and solve for x:
2.5x10^3 = (0.30 + x) / [(0.20)(0.40 - 2x)(0.30 + 4x)^4]
Solving this equation for x will give us the value of x, which represents the change in concentrations from the initial to the equilibrium state. If x is positive, it means the reaction has proceeded in the forward direction to reach equilibrium. If x is negative, it means the reaction has proceeded in the backward direction to reach equilibrium.
Conclusion:
The correct answer is option 'C'. The reaction will proceed in the backward direction to reach equilibrium.
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At 1400 K, Kc= 2.5x10 +3 for the reaction CH4(g) + 2H2S(g) CS2(g) + 4H2(g) . A 10.0L reaction vessel at 1400 K contains 2.00 mole of CH4, 3.0 mol of CS2, 3.0 mole of H2 and 4.0 mole of H2S. Thena) This reaction, is at equilibrium with above concentrations.b) The reaction will proceed in forward direction to reach equilibrium.c) The reaction will proceed in backward direction to reach equilibrium.d) The information is insufficient to decide the direction of progress of reaction.Correct answer is option 'C'. Can you explain this answer?
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At 1400 K, Kc= 2.5x10 +3 for the reaction CH4(g) + 2H2S(g) CS2(g) + 4H2(g) . A 10.0L reaction vessel at 1400 K contains 2.00 mole of CH4, 3.0 mol of CS2, 3.0 mole of H2 and 4.0 mole of H2S. Thena) This reaction, is at equilibrium with above concentrations.b) The reaction will proceed in forward direction to reach equilibrium.c) The reaction will proceed in backward direction to reach equilibrium.d) The information is insufficient to decide the direction of progress of reaction.Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about At 1400 K, Kc= 2.5x10 +3 for the reaction CH4(g) + 2H2S(g) CS2(g) + 4H2(g) . A 10.0L reaction vessel at 1400 K contains 2.00 mole of CH4, 3.0 mol of CS2, 3.0 mole of H2 and 4.0 mole of H2S. Thena) This reaction, is at equilibrium with above concentrations.b) The reaction will proceed in forward direction to reach equilibrium.c) The reaction will proceed in backward direction to reach equilibrium.d) The information is insufficient to decide the direction of progress of reaction.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 1400 K, Kc= 2.5x10 +3 for the reaction CH4(g) + 2H2S(g) CS2(g) + 4H2(g) . A 10.0L reaction vessel at 1400 K contains 2.00 mole of CH4, 3.0 mol of CS2, 3.0 mole of H2 and 4.0 mole of H2S. Thena) This reaction, is at equilibrium with above concentrations.b) The reaction will proceed in forward direction to reach equilibrium.c) The reaction will proceed in backward direction to reach equilibrium.d) The information is insufficient to decide the direction of progress of reaction.Correct answer is option 'C'. Can you explain this answer?.
At 1400 K, Kc= 2.5x10 +3 for the reaction CH4(g) + 2H2S(g) CS2(g) + 4H2(g) . A 10.0L reaction vessel at 1400 K contains 2.00 mole of CH4, 3.0 mol of CS2, 3.0 mole of H2 and 4.0 mole of H2S. Thena) This reaction, is at equilibrium with above concentrations.b) The reaction will proceed in forward direction to reach equilibrium.c) The reaction will proceed in backward direction to reach equilibrium.d) The information is insufficient to decide the direction of progress of reaction.Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about At 1400 K, Kc= 2.5x10 +3 for the reaction CH4(g) + 2H2S(g) CS2(g) + 4H2(g) . A 10.0L reaction vessel at 1400 K contains 2.00 mole of CH4, 3.0 mol of CS2, 3.0 mole of H2 and 4.0 mole of H2S. Thena) This reaction, is at equilibrium with above concentrations.b) The reaction will proceed in forward direction to reach equilibrium.c) The reaction will proceed in backward direction to reach equilibrium.d) The information is insufficient to decide the direction of progress of reaction.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At 1400 K, Kc= 2.5x10 +3 for the reaction CH4(g) + 2H2S(g) CS2(g) + 4H2(g) . A 10.0L reaction vessel at 1400 K contains 2.00 mole of CH4, 3.0 mol of CS2, 3.0 mole of H2 and 4.0 mole of H2S. Thena) This reaction, is at equilibrium with above concentrations.b) The reaction will proceed in forward direction to reach equilibrium.c) The reaction will proceed in backward direction to reach equilibrium.d) The information is insufficient to decide the direction of progress of reaction.Correct answer is option 'C'. Can you explain this answer?.
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ample number of questions to practice At 1400 K, Kc= 2.5x10 +3 for the reaction CH4(g) + 2H2S(g) CS2(g) + 4H2(g) . A 10.0L reaction vessel at 1400 K contains 2.00 mole of CH4, 3.0 mol of CS2, 3.0 mole of H2 and 4.0 mole of H2S. Thena) This reaction, is at equilibrium with above concentrations.b) The reaction will proceed in forward direction to reach equilibrium.c) The reaction will proceed in backward direction to reach equilibrium.d) The information is insufficient to decide the direction of progress of reaction.Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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