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A concave lens of glass, refractive index 1.5, has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75, it will behave as a:​
  • a)
    convergent lens of focal length 3.5R
  • b)
    divergent lens of focal length 3.5R
  • c)
    divergent lens of focal length 3.0R
  • d)
    convergent lens of focal length 3.0R
Correct answer is option 'A'. Can you explain this answer?
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Explanation:
When a concave lens of glass, refractive index 1.5, is immersed in a medium of refractive index 1.75, the following changes occur:

1. Curvature of the lens: Since the medium has a higher refractive index than the lens, the curvature of the lens will increase.

2. Focal length: The focal length of the lens will decrease as the curvature of the lens increases.

3. Behavior of the lens: A concave lens always diverges light, regardless of the medium it is immersed in. However, the degree of divergence changes with the refractive index of the medium.

Based on these changes, we can determine the correct answer to the given question.

Option A: Convergent lens of focal length 3.5R

This option is incorrect because a concave lens can never converge light, regardless of the medium it is immersed in. Therefore, option A is not the correct answer.

Option B: Divergent lens of focal length 3.5R

This option is incorrect because the lens is a concave lens, which always diverges light. Therefore, option B is not the correct answer.

Option C: Divergent lens of focal length 3.0R

This option is incorrect because the refractive index of the medium is higher than that of the lens. Therefore, the lens will have a shorter focal length, and the degree of divergence will be greater than if the lens were in air. Therefore, option C is not the correct answer.

Option D: Convergent lens of focal length 3.0R

This option is incorrect for the same reason as option A. A concave lens can never converge light, regardless of the medium it is immersed in. Therefore, option D is not the correct answer.

Conclusion:
The correct answer is option A. When a concave lens of glass, refractive index 1.5, is immersed in a medium of refractive index 1.75, it will behave as a divergent lens with a shorter focal length. The focal length will be 3.5 times the radius of curvature of the lens.
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A concave lens of glass, refractive index 1.5, has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75, it will behave as a:​a)convergent lens of focal length 3.5Rb)divergent lens of focal length 3.5Rc)divergent lens of focal length 3.0Rd)convergent lens of focal length 3.0RCorrect answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A concave lens of glass, refractive index 1.5, has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75, it will behave as a:​a)convergent lens of focal length 3.5Rb)divergent lens of focal length 3.5Rc)divergent lens of focal length 3.0Rd)convergent lens of focal length 3.0RCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A concave lens of glass, refractive index 1.5, has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75, it will behave as a:​a)convergent lens of focal length 3.5Rb)divergent lens of focal length 3.5Rc)divergent lens of focal length 3.0Rd)convergent lens of focal length 3.0RCorrect answer is option 'A'. Can you explain this answer?.
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