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A quantity of an ideal gas is collected in a graduated tube over the mercury. The volume of gas at 20degree Celsius is 50ml winds the level of mercury is 100 mm above the outside of the mercury level. The atmospheric pressure is 750mm. Volume of the gas at STP is. Given R=0.083lt.atm /k/mole The answer is 40.3ml. Plz explain?
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A quantity of an ideal gas is collected in a graduated tube over the m...
P1 = 650 torrV1 = 50 mlT1 = 20 C + 273 = 293 KP2 = 760 TorrV2 = ?T2 = 273 Kideal gas law:P1 V1 / T1 = P2 V2 / T2rearanges to:V2 = ( P1 V1 T2 ) / ( P2 T1 )V2 = (650) (50) (273) / (760) (293)V2 = 39.84 mlrounding off, much like your "50 ml" was rounded offwould give youV2 = 40 ml
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A quantity of an ideal gas is collected in a graduated tube over the m...
Understanding the Problem
To find the volume of the gas at Standard Temperature and Pressure (STP), we need to understand the given conditions and the adjustments for pressure and temperature.
Given Data
- Initial Volume (V1) = 50 ml
- Temperature (T1) = 20°C = 293 K
- Atmospheric Pressure (P_atm) = 750 mm Hg
- Mercury Column Height = 100 mm Hg
- Total Pressure (P_total) = P_atm + Mercury Height = 750 mm + 100 mm = 850 mm Hg
- R = 0.083 L·atm / K·mole
Converting Units
First, convert the total pressure from mm Hg to atm:
- P_total = 850 mm Hg / 760 mm Hg/atm = 1.1184 atm
Using the Ideal Gas Law
The Ideal Gas Law states:
PV = nRT
We need to find the volume at STP (P = 1 atm, T = 273 K).
Finding the Number of Moles
Using the initial conditions:
- n = (P_total * V1) / (R * T1)
Substituting the values:
- n = (1.1184 atm * 0.050 L) / (0.083 L·atm / K·mole * 293 K)
- n = 0.00204 moles
Calculating Volume at STP
At STP:
- V2 = (n * R * T2) / P2
Where T2 = 273 K and P2 = 1 atm:
- V2 = (0.00204 moles * 0.083 L·atm / K·mole * 273 K) / 1 atm
- V2 = 0.0403 L = 40.3 ml
Conclusion
Thus, the volume of gas at STP is 40.3 ml.
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The atmospheric lapse rateFor small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantityTP(1 – λ)/λ has a uniform value through the layers of troposphere.(M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)Q. The value of theoretical lapse rate on the earth is (use g = 9.8 m/s2 ; R = 8.3 J/mol-k and M = 29 g/mol)

The atmospheric lapse rateFor small volumes of gas, according to kinetic theory of gases, all parts of the gas are at the same temperature. But for huge volumes of gas like atmosphere, assumption of a uniform temperature throughout the gas is not valid. Different parts of the atmosphere are at different temperatures. Apart from the surface of the earth, variations also occur in temperature at different heights in the atmosphere.The decrease in temperature with height called the atmospheric lapse rate is similar at various locations across the surface of the Earth. By analyzing the data collected at various locations, it is found that average global lapse rate is – 6.7 °C/Km.The linear decrease with temperature only occurs in the lower part of the atmosphere called the troposphere. This is the part of the atmosphere in which weather occurs and our planes fly. Above the troposphere is the stratosphere, with an imaginary boundary separating the two layers. In the stratosphere, temperature tends to be relatively constant.Absorption of sunlight at the Earth’s surface warms the troposphere from below, so vertical convection currents are continually mixing in the air. As a parcel of air rises, its pressure drops and it expands. The parcel does work on its surrounding, so that its internal energy and therefore, its temperature drops. Assume that the vertical mixing is so rapid as to be adiabatic and the quantityTP(1 – λ)/λ has a uniform value through the layers of troposphere.(M is molecular mass of the air, R is universal gas constant, g is gravitational acc., P and T are pressure and temperature respectively at the point under consideration and y is height.)Q. Mechanical equilibrium of the atmosphere requires that the pressure decreases with altitude according to . Assuming free fall acceleration to be uniform, then lapse rate is given by

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A quantity of an ideal gas is collected in a graduated tube over the mercury. The volume of gas at 20degree Celsius is 50ml winds the level of mercury is 100 mm above the outside of the mercury level. The atmospheric pressure is 750mm. Volume of the gas at STP is. Given R=0.083lt.atm /k/mole The answer is 40.3ml. Plz explain?
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A quantity of an ideal gas is collected in a graduated tube over the mercury. The volume of gas at 20degree Celsius is 50ml winds the level of mercury is 100 mm above the outside of the mercury level. The atmospheric pressure is 750mm. Volume of the gas at STP is. Given R=0.083lt.atm /k/mole The answer is 40.3ml. Plz explain? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A quantity of an ideal gas is collected in a graduated tube over the mercury. The volume of gas at 20degree Celsius is 50ml winds the level of mercury is 100 mm above the outside of the mercury level. The atmospheric pressure is 750mm. Volume of the gas at STP is. Given R=0.083lt.atm /k/mole The answer is 40.3ml. Plz explain? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A quantity of an ideal gas is collected in a graduated tube over the mercury. The volume of gas at 20degree Celsius is 50ml winds the level of mercury is 100 mm above the outside of the mercury level. The atmospheric pressure is 750mm. Volume of the gas at STP is. Given R=0.083lt.atm /k/mole The answer is 40.3ml. Plz explain?.
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